std :: bind和boost :: bind与多态性之间的区别
我有一个派生类,我绑定一个虚拟函数,我没有在这个类重写,所以我希望调用父类之一。
使用boost(1.55)很好,但如果我从C ++ 11切换到std :: bind,它拒绝编译
I have a derived class from which I bind a virtual function that I did not override in this class, so I'm hoping to call the one of the parent class.
It works nice with boost (1.55), but if I switch to std::bind from C++11, it refuse to compile with
错误C2100:非法间接
1>功能(1152):参见函数模板实例化_Rx std :: _ Pmf_wrap< _Pmf_t,_Rx,_Farg0,_V0_t,_V1_t,_V2_t,_V3_t ,_V4_t,_V5_t,> :: operator()(_ Wrapper&)const'
1>与
1> [
1> _Rx = bool,
1> _Pmf_t = bool(__thiscall Base :: *)(void),
1> _Farg0 = Base,
1> _V0_t = std :: _ Nil,
1> _V1_t = std :: _
1> _V2_t = std :: _ Nil,
1> _V3_t = std :: _Nil,
1> _V4_t = std :: _Nil,
1> _V5_t = std :: _Nil,
1> = std :: _ Nil,
1> _Wrapper = Derived
1>]
error C2100: illegal indirection 1> functional(1152) : see reference to function template instantiation '_Rx std::_Pmf_wrap<_Pmf_t,_Rx,_Farg0,_V0_t,_V1_t,_V2_t,_V3_t,_V4_t,_V5_t,>::operator ()(_Wrapper &) const' being compiled 1> with 1> [ 1> _Rx=bool, 1> _Pmf_t=bool (__thiscall Base::* )(void), 1> _Farg0=Base, 1> _V0_t=std::_Nil, 1> _V1_t=std::_Nil, 1> _V2_t=std::_Nil, 1> _V3_t=std::_Nil, 1> _V4_t=std::_Nil, 1> _V5_t=std::_Nil, 1> =std::_Nil, 1> _Wrapper=Derived 1> ]
这是一个最小代码
class Runnable { virtual bool Run() =0;};
class Base : public Runnable { bool Run() {/*do stuff*/ return true;}};
class Derived : public Base {};
Derived d;
std::function<bool()> f = std::bind(&Derived::Run,std::ref(d)); //Do not compile
std::function<bool()> f = boost::bind(&Derived::Run,boost::ref(d)); //compile
这不是一个大问题,因为我可以坚持boost,
It's not a major issue, since I can stick with boost, but I would really want to know what's the difference between the two.
我已经在这里检查了几个问题,但我不认为它将如何与这。
Checked stroustrup的网站太这里,但我没有看看任何可以解释这个行为的东西。
我在这里缺少什么?
I've checked few questions in here but I don't think how it will be related to this.
Checked stroustrup's site too here, but I did not see anything that could explain this behaviour.
What am I missing here ?
Ps:我使用VS2012 Update 4,如果这可以帮助
Ps: I work with VS2012 Update 4, if this can help
Visual Studio 2012有很多与 std :: function
和 std :: bind
。这是其中之一;该代码将在Visual Studio 2010和Visual Studio 2013中工作。
Visual Studio 2012 has a lot of bugs relating to std::function
and std::bind
. This is one of them; the code will work in both Visual Studio 2010 and Visual Studio 2013.
最好的选择是只使用Boost.Function和Boost.Bind。
The best choice is to use Boost.Function and Boost.Bind exclusively.