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xpath 选择两个节点之间的元素

分类: 技术问答 • 2022-03-19 12:24:56

xpath 选择两个节点之间的元素

问题描述：

这是我的 HTML:

<table dir = "rtl .......">
<tbody>
<script src = "get.aspx?type=js&file=ajax&rev=3"......>
<script language = "JavaScript" src = "get.aspx?type=js&file=mc&rev=6"></script>
<script>..</script>
<tr>
  <td class = "d2"...>..</td>
</tr>
<tr>..</tr> <--
<tr>..</tr> <--
<tr>..</tr> <-- these elements
<tr>..</tr> <--
<tr>..</tr> <--
<tr>..</tr> <--
<tr>..</tr> <--
<tr>
  <td class = "d2"...>..</td>
</tr>
<script>..</script>
<tr>..</tr>
<tr>..</tr>
<tr>..</tr>

如何计算或选择两个 元素之间的所有 元素，其 id 为 d2?

How would I count or select all <tr> elements between the two <td> elements whose id is d2?

答

xpath 会很长，所以要振作起来:

count(//tr[preceding-sibling::tr/td[@class = 'd2']][count(.|//tr[following-sibling::tr/td[@class = 'd2']])=count(//tr[following-sibling::tr/td[@class = 'd2']])])

要选择实际节点而不仅仅是计数，只需删除第一个计数:

To select the actual nodes and not have just the count, simply remove the first count : 

//tr[preceding-sibling::tr/td[@class = 'd2']][count(.|//tr[following-sibling::tr/td[@class = 'd2']])=count(//tr[following-sibling::tr/td[@class = 'd2']])]

这里发生了各种各样的事情:

There are various things happening here notably:

  • Select start node by selecting preceding sibling's child node tr/td with id='2'
  • Select end node by selecting following sibling's child node tr/td with id='2'
  • Use kaycian method : http://www.dpawson.co.uk/xsl/sect2/muench.html#d9940e108 to get the intersection between the two nodes.
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