如何验证Selenium 2中不存在元素

问题描述：

在Selenium 2中，我要确保驱动程序已加载的页面上的元素不存在.我在这里包括了我的幼稚实现.

In Selenium 2 I want to ensure that an element on the page that the driver has loaded does not exist. I'm including my naive implementation here.

    WebElement deleteLink = null;
    try {
        deleteLink = driver.findElement(By.className("commentEdit"));
    } catch (NoSuchElementException e) {

    }
    assertTrue(deleteLink != null);

有没有一种更优雅的方法可以从根本上验证断言是否引发了NoSuchElementException?

Is there a more elegant way that basically verifies to assert that NoSuchElementException was thrown?

答

如果您正在使用junit进行测试，而这只是您要进行的测试，则可以使测试使用来期待异常

If you are testing using junit and that is the only thing you are testing you could make the test expect an exception using

@Test (expected=NoSuchElementException.class)
public void someTest() {
    driver.findElement(By.className("commentEdit"));
}

或者您可以使用findElements方法返回元素列表，或者如果找不到元素列表则返回空列表(不抛出NoSuchElementException):

Or you could use the findElements method that returns an list of elements or an empty list if none are found (does not throw NoSuchElementException):

...
List<WebElement> deleteLinks = driver.findElements(By.className("commentEdit"));
assertTrue(deleteLinks.isEmpty());
...

或

....
assertTrue(driver.findElements(By.className("commentEdit")).isEmpty());
....

如何验证Selenium 2中不存在元素

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