为什么我的PHP页面会响应整个HTML源代码，而不仅仅是我正在回应的数据？

问题描述：

I am trying to communicate back and forth with the server with the help of jQuery.

This is my simple scenario:

Send data through html form using jQuery post method.
Receive data on the server side end echo it back again.
Receive same data on the client side in the form of jQuery callback and do something with data (console.log in the broser)

Now my problem is that php is returning source html code with tags, instead of data that has been received ? So if I type "Hello" in the form field on the client side, php is returning whole html source from the page. Why is that ?

Html:

<form action="#">
     <textarea name="content" id="content" rows="8" cols="40"></textarea>
        <p><button>Click to submit</button></p>
    </form>

jquery:

    (function(){
            $("form").on("submit",function(e){
                $.post("save.php",$(this).serialize(),function(data){
                    alert(data);
                })
            e.preventDefault();
            })
    }());

PHP:

<!DOCTYPE HTML>
<html charset="utf-8">
    <head>
        <title>Index</title>
        <link rel="stylesheet" href="path-to-stylesheet.css" type="text/css"/>
    </head>
    <body>
        <?php
            echo $_POST['content'];
        ?> 
    <script src=""></script>
    </body>
</html>

答

You are sending a complete html page back to the browser, that's why you don't receive only the data. Change your php file to the following and it should work as expected:

<?php
echo $_POST['content'];
?>

Why did PHP return a whole html page in your case?

PHP parses the whole save.php file
If there are no <?php ?> tags, the whole content is left untouched and will be sent to the browser as it is
If it finds any <?php ?> tags the parser interprets the code and outputs it in the same place

Example

save.php

<!DOCTYPE HTML>
<html charset="utf-8">
    <head>
        <title>Index</title>
        <link rel="stylesheet" href="path-to-stylesheet.css" type="text/css"/>
    </head>
    <body>
        <?php
            echo $_POST['content'];
        ?> 
    <script src=""></script>
    </body>
</html>

The parser finds one <?php ?> tag:

        <?php
            echo $_POST['content'];
        ?>

And interprets it: (simply assuming that $_POST['content'] == 'john smith')

        john smith

Now, the interpreted code gets inserted and replaces the php tag in the original content:

<!DOCTYPE HTML>
<html charset="utf-8">
    <head>
        <title>Index</title>
        <link rel="stylesheet" href="path-to-stylesheet.css" type="text/css"/>
    </head>
    <body>
        john smith
    <script src=""></script>
    </body>
</html>

Finally, this is sent to the browser and gets processed by the jQuery Ajax callback.

答

Assuming this is your save.php :

<!DOCTYPE HTML>
<html charset="utf-8">
    <head>
        <title>Index</title>
        <link rel="stylesheet" href="path-to-stylesheet.css" type="text/css"/>
    </head>
    <body>
        <?php
            echo $_POST['content'];
        ?> 
    <script src=""></script>
    </body>
</html>

Just do a json_encode and parse jSON with your ajax call :

save.php

<?php
    echo json_encode($_POST['content']);
?>

jQuery

$.post("save.php",
    $(this).serialize(),
    function(data){
        alert(data);
    }, 'json');

为什么我的PHP页面会响应整个HTML源代码，而不仅仅是我正在回应的数据？

Why did PHP return a whole html page in your case?

Example

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