当限制和增量是动态的时,如何获得for循环的最后一次迭代?
I have seen some question related to this one like
How to check for last loop when using for loop in php?
Last iteration of enhanced for loop in java
but I am not getting exact solution because in my case increment and end limit both are dynamic.
Requirement:- I do not want comma after last element printed.
$inc=11;
$end=100;
for($i=1;$i<=$end;$i=$i+$inc){
echo $i==$end?$i:"$i,"; // 1,12,23,34,45,56,67,78,89,100
}
In above code I know that last element($i) will be 100($end).
So I can write condition as $i==$end but in below case it won't work.
$inc=12; // Now $inc is 12
$end=100;
for($i=1;$i<=$end;$i=$i+$inc){
echo $i==$end?$i:"$i,"; // 1,13,25,37,49,61,73,85,97,
}
Now last element 97 has comma which I need to remove.
Thanks in advance.
我见过一些与此相关的问题,如 p>
但我没有得到确切的解决方案,因为在我的情况下增量 strong>和结束限制 strong >两者都是动态 strong>。 p>
要求: - strong>我打印最后一个元素后不想使用逗号。 p>
在上面的代码中我知道最后一个元素 ($ i) em>将 100($ end) em>。 p>
所以我可以将条件写为 $ i == $ end strong>,但在下面的情况下它不起作用。 p>
现在最后一个元素97有逗号我需要 删除。 p>
提前致谢。 p>
div>
$ inc = 11;
$ end = 100;
for($ i = 1; $ i&lt; = $ end; $ i = $ i + $ inc){
echo $ i == $ end?$ i:“$ i,”; // 1,12,23,34,45,56,67,78,89,100
}
code> pre>
$ INC = 12; //现在$ inc是12
$ end = 100;
for($ i = 1; $ i&lt; = $ end; $ i = $ i + $ inc){
echo $ i == $ end?$ i : “$ I”; // 1,13,25,37,49,61,73,85,97,
}
code> pre>
You can just use,
echo $i+$inc>$end?$i:"$i,";
It checks whether this is the last possible iteration instead.
Use rtrim to remove the last comma
$inc = 12; // Now $inc is 12
$end = 100;
$print = '';
for($i=1;$i<=$end;$i=$i+$inc){
$print .= ($i==$end)? $i : "$i,"; // 1,13,25,37,49,61,73,85,97,
}
$print = rtrim($print, ',');
echo $print;
Keep it simple:
$numbers = range(0, $end, $inc);
$string = implode(",", $numbers);
echo $string;
You can see it here: https://3v4l.org/BRpnH
;)
You can do it in this way :
<?php
$inc=4;
$end=10;
for($i=1;$i<=$end;$i=$i+$inc){
echo ($i+$inc-1)>=$end?$i:"$i,"; // 1,5,9
}
?>
This code is working on prime number case also not given you result like // 1,13,25,37,49,61,73,85,97,
always gives you result like // 1,13,25,37,49,61,73,85,97
no comma added after any prime number.