C ++按值而不是按位置擦除向量元素?

C ++按值而不是按位置擦除向量元素?

问题描述:

vector<int> myVector;

,让我们说向量中的值是这个(按这个顺序):

and lets say the values in the vector are this (in this order):

5 9 2 8 0 7


$ b b

如果我想删除包含值8的元素,我想我会这样做:

If I wanted to erase the element that contains the value of "8", I think I would do this:

myVector.erase(myVector.begin()+4);

因为这会删除第4个元素。但是有没有办法删除基于值8的元素?喜欢:

Because that would erase the 4th element. But is there any way to erase an element based off of the value "8"? Like:

myVector.eraseElementWhoseValueIs(8);

还是我只需要遍历所有向量元素并测试它们的值?

Or do I simply just need to iterate through all the vector elements and test their values?

std :: remove()

#include <algorithm>
...
vec.erase(std::remove(vec.begin(), vec.end(), 8), vec.end());

此组合也称为 erase-remove idiom