Java布尔值始终为true
问题描述:
我在使用学校的Java代码时遇到了麻烦-我试图创建一个采用布尔值的构造函数,然后在以后使用它,但是出于某种原因,它始终是正确的.有人可以告诉我我在做什么错吗?
I'm having trouble with my school Java code - I'm trying to create a constructor that takes a boolean value, and then uses it later, but for some reason it's always true. Could anyone tell me what I'm doing wrong?
我正在发布我的整个代码,我想稍微编辑一下可以使我的问题更加清楚,但是看来这只会造成混乱.
I'm posting my entire code, I thought redacting it a little would make my problem clearer, but it seems it only created confusion.
import java.util.*;
public class L3_Z6 {
public static void main(String[] args) {
// TODO Auto-generated method stub
class FunnyString{
private boolean ascii;
private String slowo;
private char separator;
public FunnyString (String slowo, char separator, boolean ascii){
this.slowo=slowo;
this.separator=separator;
this.ascii=ascii;
}
public FunnyString (String slowo, char separator){
this(slowo, separator, false);
}
public FunnyString (String slowo, boolean ascii){
this(slowo,'-', ascii);
}
public FunnyString (String slowo){
this(slowo,'-', false);
}
public void setAscii (boolean a){
ascii=a;
}
public void setChar (char b){
separator=b;
}
public String toString (){
int dlugosc = slowo.length();
int licznik = 0;
String wynik="";
do{
if(ascii=false){
wynik+=slowo.charAt(licznik);
}
if(ascii=true){
wynik+=(int)slowo.charAt(licznik);
}
if(licznik!=dlugosc-1)
wynik+=separator;
licznik++;
}while (licznik!=dlugosc);
wynik+="\n";
return wynik;
}
}
FunnyString w1=new FunnyString("Kaktus");
FunnyString w2=new FunnyString("Eukaliptus",'*');
FunnyString w3=new FunnyString("Yuka",true);
System.out.println(w1);
System.out.println(w2);
System.out.println(w3);
w1.setAscii(true);
w1.setChar('*');
System.out.println(w1);
w3.setAscii(false);
w3.setChar('!');
System.out.println(w3);
}
}
答
在您的 if
条件下,您使用分配而不是比较.
In your if
conditions, you're using assignment instead of comparison.
更改此
if(ascii=false){
wynik+=slowo.charAt(licznik);
}
if(ascii=true){
wynik+=(int)slowo.charAt(licznik);
}
对此
if(ascii==false){
wynik+=slowo.charAt(licznik);
}
if(ascii==true){
wynik+=(int)slowo.charAt(licznik);
}