为返回的数据添加顺序号

问题描述：

Newb here attempting something new (for me)

What I am attempting: I am attempting to create an idea number that iterates with each return, so the incident report for the giant kaiju (strange beast - aka Godzilla and friends) has an individual case number that is created programmatically). This means return one would be #1, return two would be #2, returned 3 would be #3 et al.

What I have done: I've attempted to put my int at the beginning, in the middle, at the end, after the return, etc, but regardless of where I put it, i always get the same number (12). I've read about iterating over at php.net, and looked through stack overflow and other places but i've not found something i could internalize/understand enough to replicate.

function __toString(){
$kID = 1;//kaiju incident number

    $myReturn = "<p> Incident ID: kID" . $kID ;
    $kID++; //not iterating thru
    $myReturn .= $kID ;

    $myReturn .= " | Massive Terrestial Organsim Reported: " . $this->movTitle . "   " ;
    $myReturn .= " | Location Name: " . $this->entWhat. " ";
    $myReturn .= " | Severity of Incident Reported: " . $this->movRating . "</p>" ;

    return $myReturn;

Newb在这里尝试新事物（对我来说） p>

我在尝试什么：我正在尝试创建一个与每次返回迭代的创意编号，因此巨型kaiju（奇怪的野兽 - 又名哥斯拉和朋友）的事件报告具有以编程方式创建的个别案例编号。这意味着返回一个将是＃1，返回两个将是＃2，返回3将是＃3等人。 p>

我做了什么：我试图把我的int放在在开始，中间，结束，返回之后等等，但不管我把它放在哪里，我总是得到相同的数字（12）。我已经阅读了关于在php.net上迭代的内容，并查看了堆栈溢出和其他地方，但我没有找到可以内化/理解足以复制的东西。 p>

   function __toString（）{
 $ kID = 1; // kaiju事件编号
 
 $ myReturn =“＆lt; p＆gt;事件ID：kID”。  $ kID; 
 $ kID ++;  //不通过
 $ myReturn迭代。= $ kID; 
 
 $ myReturn。=“| Massive Terrestial Organsim报道：”。  $ this-＆gt; movTitle。  “”; 
 $ myReturn。=“|位置名称：”。  $这 - ＆GT; entWhat。  “”; 
 $ myReturn。=“|事件严重程度报告：”。  $ this-＆gt; movRating。  “＆LT; / P＆gt;” 中 ; 
 
返回$ myReturn; 
  code>  pre> 
  div>

答

$kID is set to 1 each time the function is called. Make it static so it will retain it's values across function calls:

static $kID = 1;//kaiju incident number

Also:

$myReturn = "<p> Incident ID: kID" . $kID;
$kID++;

答

Right now every time your function is called, this code executes:

$kID = 1
$myReturn = $kID;
$kID++; 
$myReturn .= $kID ;

So $kID is being set to 1, then 2, hence the 12 in your output.

You need to define $kID outside your function. Maybe a rewrite like this:

function __toString(&$kID){
  $myReturn = "<p> Incident ID: kID" . $kID++ ;

为返回的数据添加顺序号

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