使用Jackson将带有私有列表属性的JSON数组反序列化为对象

问题描述：

JSON字符串，例如:

A JSON string like:

[
  "a", "b", "c"
]

通常将反序列化为List<String>.但是我有一个看起来像这样的课:

Would usually be deserialized to List<String>. But I have a class that looks like this:

public class Foo {
  private List<String> theList;

  public Foo(List<String> theList) {
      this.theList = theList;
  }

  public String toString() {
      return new ObjectMapper().writeValueAsString(theList);
  }

  // ... more methods
}

现在我想将上述JSON字符串反序列化为类Foo的对象，如:

Now I want to deserialize the above JSON string into an object of class Foo like:

Foo foo = new ObjectMapper().readValue(jsonString, Foo.class);

那怎么可能?

我已经尝试将@JsonCreator与构造函数一起使用，但总是得到:

I've already tried to use @JsonCreator with the constructor but always get:

JsonMappingException: Can not deserialize instance of ... out of START_ARRAY token

答

对于Jackson 2.4.3，此

With Jackson 2.4.3, this

@JsonCreator
public Foo(List<String> theList) {
    this.theList = theList;
}
...

String jsonString = "[\"a\", \"b\", \"c\"]";
Foo foo = new ObjectMapper().readValue(jsonString, Foo.class);
System.out.println(foo.getTheList());

为我工作.它打印

[a, b, c]

使用Jackson将带有私有列表属性的JSON数组反序列化为对象

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