GSON泛型序列化

问题描述：

可能重复:
使用gson反序列化泛型

Possible Duplicate:
deserializing generics with gson

所以我需要做:

Type fluentType = new TypeToken<BruteForceFluentImpl<GtlDigestor.Data>>() {}.getType();

代替

Type fluentType = new TypeToken<Fluent<T>>() {}.getType(); // <-- i want to be able to do something like this.

String json = gson.toJson(fluent, fluentType);

这意味着每次我必须为Fluent类指定不同的类型参数时，都需要更改代码以进行指定.现在，类型参数是GtlDigestor.Data.

This means that every time I have to specify a different type parameter for the Fluent class, I need to change my code in order to specify it. Right now, the type parameter is GtlDigestor.Data.

我该怎么做? (第二行代码无效)

How do I do this? (the second line of code won't work)

答

您需要在运行时告诉Gson实际的参数化类型(例如，BruteForceFluentImpl<GtlDigestor.Data>，包括实际的运行时原始类型和实际的类型参数值)，因为Gson需要保存此信息.

You need to tell Gson the actual parameterized type (e.g. BruteForceFluentImpl<GtlDigestor.Data>, including the actual runtime raw type and the actual type parameter value) at runtime, because Gson needs to save this information.

使用TypeToken是获取Type的最简单方法，但是要使用它，您必须在源代码中对确切的类型进行硬编码(没有像T这样的类型参数).如果您想将代码放入将用于不同类型的方法中，则此方法可能应接受Type作为参数，调用者需要传递该参数.编码在调用方的位置，每个位置大概只能使用固定类型.

Using TypeToken is the easiest way to get a Type, but to use it you must hard-code the exact type in the source (no type parameters like T). If you would like to put the code in a method that will be re-used with different types, then perhaps this method should accept the Type as a parameter, which the caller needs to pass in. The type can then be hard-coded at the caller's location, each of which presumably only uses a fixed type.

或者，如果您需要基于原始类型和类型参数在运行时完全动态地生成Type，请参阅我对问题

Or, if you need to generate the Type completely dynamically at runtime based on the raw type and type parameters, see my answer for the question here.

GSON泛型序列化

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