PHP：将Array值转换为变量

问题描述：

I´m making a form, and I want to change the value of the POST into a variable. But I'm doing it wrong somehow.

Check the sample:

$_POST['name'] = $name;
$_POST['age'] = $age;
$_POST['country'] = $country;

This error pops: Parse error: syntax error, unexpected T_VARIABLE on the first $_POST

我正在创建一个表单，我想将POST的值更改为变量。但是我以某种方式做错了。 p>

检查示例： p>

  $ _ POST ['name'] = $ name;  
 $ _POST ['age'] = $ age; 
 $ _POST ['country'] = $ country; 
  code>  pre> 
 
 此错误弹出： 第一个$ _POST  p> 
  div>上的解析错误：语法错误，意外的T_VARIABLE  code>

答

While everyone else is entirely correct to point that you shouldn't be assigning values to the $_POST superglobal, it is possible for you to make such an assignment. The $_POST superglobal is just an array, after all, and so it acts like one.

The error you're seeing is because PHP is recognizing $_POST['name'] as being part of the previous statement. Check to make sure that you have properly ended the previous statement (i.e. the line before $_POST['name'] = $name ends with a ;).

You probably do want to be assigning $_POST['name'] to a variable, rather than the other way around as you have it now, but that's not what's causing the error.

答

You don't programmatically set $_POST variables. These are set by the server based on what was POST'ed to that page(via forms or otherwise).

So I'm fairly sure you want:

$name = $_POST['name'];
$age = $_POST['age'];
$country = $_POST['country'];

This is because the assignment operator works as such:

a = b

Set a to the value of b.

答

go the other way:

$name = $_POST['name'];
$age = $_POST['age'];
$country = $_POST['country'];

答

Assignment works right to left, so to get the values from the into a variable you'd have to do:

$name = $_POST['name'];
...

Your code above does not contain any syntax error, it must be from somewhere else.

答

You have this backwards, it should be:

$name = $_POST["name"];  
$age= $_POST["age"];  
$country= $_POST["country"];

The value to the right of the = gets assigned to the left. As is you are trying to replace the post variable with an unassigned variable.

PHP：将Array值转换为变量

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