从php中的数组获取值并爆炸

问题描述：

I have this the values of in my array as

$itsthere = (item1-0-100, item2-0-50, item3-0-70, item4-0-50, item5-0-100);

If the user enter the value item3 he has to get 70 which is present in array. I tried alot using explode but its not showing proper value. Can any one help me.

我的数组中的值为 p>

   $ itsthere =（item1-0-100，item2-0-50，item3-0-70，item4-0-50，item5-0-100）; 
  code>  pre> 
 
 如果用户输入值 item3  code>，他必须得到 70  code>，它存在于数组中。 我尝试了很多使用爆炸但它没有显示正确的价值。 任何人都可以帮助我。 p> 
  div>

答

Try this :

    $item = 'item3';
    $itsthere = array('item1-0-100', 'item2-0-50', 'item3-0-70', 'item4-0-50', 'item5-0-100');

    foreach($itsthere as $there)
    {
        $exp = explode('-',$there);
        if($exp[0] == 'item3') {
            echo $val = $exp[2];
        };
    }

答

Try with:

$itsthere = array(
  'item1-0-100',
  'item2-0-50',
  'item3-0-70',
  'item4-0-50',
  'item5-0-100'
);

$search = 'item3';
$output = '';

foreach ( $itsthere as $value ) {
  if ( strpos($search . '-', $value) === 0 ) {
    $output = explode('-', $value)[2];
    break;
  }
}

答

When you say item3 are you refering to the third position or the item3 as array key? I think you can create a assoc array and make item names as key

$isthere = array('item1' => '0-100', 'item2' => '0-50' ,'item3' => '0-70', ....,);
echo $isthere['item3']; // This would give you the value.

If you only want to know if this key is in the array use array_key_exists.

从php中的数组获取值并爆炸

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