通过PHP中的foreach进行验证

问题描述：

Hi can some one help me out with the following. This prints every time Empty! or Full! whenever there is a blank or a non blank text box is detected.

What I need is the following;

Out of the series of text boxes (in the array) even only one text is detected blank just echo Empty! ONLY ONCE not every time there a blank textbox.
If ONLY all the text boxes are non-blank, then echo Full! only ONCE!

How do you suggest that I change the following? Thank you.

if(isset($_POST['Save']))
{
    if(is_array($_POST['name']))
    {
    foreach($_POST['name'] as $Value)
        {if($Value == '')
            {
            echo "<table border='1'><tr><td>Response</td></tr></table>";
            echo "Empty!";
            } 
            else 
            {
            echo "<table border='1'><tr><td>Response</td></tr></table>";
            echo "Full";
            }
        }
    }
}

EDIT

echo "<td><input style='width:60px' type='text' name='name[]' id='vtext' class='sc_two'     size='80' maxlength='5'></td>

then in a validation code I have the following;

if(isset($_POST['Save']))
{
    if($_POST['name']=='')
    {
    echo "<table border='1'><tr><td>Responses</td></tr></table>";
    echo "Empty";} 
    else 
    {
    echo "<table border='1'><tr><td>Responses</td></tr></table>";
    echo "Saved!";}
}

您可以通过以下方式帮助我。每当检测到空白或非空白文本框时，Empty！ code>或 Full！ code>就会打印出来。 p>

我需要的是以下内容; p>


 在一系列文本框中（在数组中）甚至 只检测到一个文本空白只有echo 空！ code>  ONLY ONCE  strong>并非每次都有空白文本框。 p>  li> 
 
  如果仅 strong>所有文本框都是非空白，则仅回显 Full！ code> 
  ONCE！ strong>  p>  li> \  n  ol> 
 
 
您如何建议我更改以下内容？ 谢谢。 p> 
 
 

  if（isset（$ _ POST ['Save']））
 {
 if if（is_array（$ _ POST ['name']））
  {
 foreach（$ _ POST ['name'] as $ Value）
 {if（$ Value ==''）
 {
 echo“＆lt; table border ='1'＆gt;＆lt; tr＆gt;＆lt;  ; td＆gt;响应＆lt; / td＆gt;＆lt; / tr＆gt;＆lt; / table＆gt;“; 
 echo”空！“; 
} 
其他
 {
 echo”＆lt; table border ='1'＆gt;  ;＆lt; tr＆gt;＆lt; td＆gt;响应＆lt; / td＆gt;＆lt; / tr＆gt;＆lt; / table＆gt;“; 
 echo”完整“; 
} 
} 
} 
} 
   code  >  pre> 
 
  编辑 strong>  p> 
 
 
  echo“＆lt; td＆gt;＆lt; input style ='width：60px'  type ='text'name ='name []'id ='vtext'class ='sc_two'size ='80'maxlength ='5'＆gt;＆lt; / td＆gt; 
  code>  pre> \  n 
 然后在验证码中我有以下内容;  p> 
 
 
  if（isset（$ _ POST ['Save']））
 {
 if（  $ _POST ['name'] ==''）
 {
 echo“＆lt; table border ='1'＆gt;＆lt; tr＆gt;＆lt; td＆gt;响应＆lt; / td＆gt;＆lt; / tr＆gt;＆lt; / 表＆gt;“; 
  echo“Empty”;} 
 else 
 {
 echo“＆lt; table border ='1'＆gt;＆lt; tr＆gt;＆lt; td＆gt; Responses＆lt; / td＆gt;＆lt; / tr＆gt;＆lt; / table＆gt;”  ; 
 echo“已保存！”;} 
} 
  code>  pre> 
  div>

答

if(isset($_POST['Save'])) {
    if(is_array($_POST['name'])) {

        $result = 'Full!'; // Result defaults to 'Full!'

        // But if we find an empty value we change it to 'Empty!'
        foreach($_POST['name'] as $value){
            if($value === ''){
                $result = 'Empty!';
                break;
            }
        }

        // Output the response
?>
        <table border="1"><tr><td>Response</td></tr></table>
        <?=$result?>
<?php
    }
}

答

if(isset($_POST['Save']))
{
    if(is_array($_POST['name']))
    {
     $full = 0;
    foreach($_POST['name'] as $Value){
        if($Value == '')
            {
            $full = ++;
            } 
        }
    }
    echo "<table border='1'><tr><td>Response</td></tr></table>";
    echo $full == 0 ? "Full" : "Empty" //Shorthand if notation
}

You have to run your checks then output the response outside the loop.

答

You don't need a loop, use array_search to tell if there's an empty element in the array.

if (array_search('', $_POST['name'])) {
  $result = 'Empty!';
} else {
  $result = 'Full!';
}
echo '<table border="1"><tr><td>Response</td></tr></table>';
echo $result;

通过PHP中的foreach进行验证

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