如何使用Ajax获取URL的标题，描述，image_url，如在Facebook上共享链接[关闭]
I am working on a project where if a user submits a URL, it should grab the title, images, and description from that URL and then give an option to change between images.
When submitted it should post those values.
我正在开发一个项目，如果用户提交了一个URL，它应该抓住标题，图片和描述 从该URL开始，然后选择在图像之间进行更改。 p>
提交时，它应该发布这些值。 p> div>
Facebook, Google+ gets image, title, description from two known ways.
1) Most of the well-know websites gives og tags. It contains title, description, image http://ogp.me/
2) meta tags inside head tag of html will also be published by many sites. You can make use of that also.
For more explanation see the following link.
I advise that you make a PHP page that parses the information and returns the data to you Ajax function. So to summarize, you'll want to google: "PHP Parsing HTML" and "Ajax PHP Retrieve Data".