为什么这个正则表达式匹配正面？

问题描述：

Given the pattern ^[a-zA-Z0-9 .\-_]+$ and the string te\\st, why is the match positive? I'm using this to validate usernames and I don't want people to put slashes in their usernames, it messes with URLs.

I'm calling ereg($pattern, $username), running PHP version 5.2.8.

给定模式^ [a-zA-Z0-9。\ -_] + $ 代码>和字符串 te \\ st code>，为什么匹配正面？我正在使用它来验证用户名，我不希望人们在他们的用户名中加入斜杠，它会混淆URL。 p>

我正在调用 ereg（$ pattern， $ username） code>，运行PHP版本5.2.8。 p> div>

答

ereg is crazy. I recommend avoiding it. You should try using preg_match for this:

$count = preg_match('/^[a-zA-Z0-9 .\-_]+$/', 'te/\st', $matches);
print_r($matches); // empty array (no matches)
print $count; // 0 (no matches)

答

^[a-zA-Z0-9 ._-]+$

Will work as well. To match a literal - in a character class it is usually safest to place it right before the ending ], or right after the opening [ when using ereg (POSIX). You should be able to escape out the - but for some reason when escaping it directly after the . seems to fail. Anyway there is a solution if you must use ereg. Really good question as to why that fails, the . should just be a normal character within the character class. Ereg is buggy.

Further reference.

And if you have the choice use preg (PCRE)...

为什么这个正则表达式匹配正面？

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