在PHP中获得前几个月

问题描述：

I need to display 3 month from the previous month in php

Here is what I have tried so far

<select style='width: 112px;' name='PayMonth'>
<option name="PayMonth" value=''>Select Month</option>   
<?php
for($i = 1 ; $i <= 12; $i++)
{
$allmonth = date("F",mktime(0,0,0,$i,1,date("Y")))
?>
<option value="<?php echo $i; ?>" ><?php echo date("F",mktime(0,0,0,$i,1,date("Y")));?>
</option>
<?php
}?>

This will display all months

But how can I display on 3 months from current month

i.e.,

If current month is april it should show Feb, Mar, Apr

If current month is jan it should show nov, dec, jan

I tried..

<?php

$month = date("m");

?>

But in the loop I am confused with

for($i = 1 ; $i <= $month; $i++)

我需要在上个月显示3个月的php p>

这里是我到目前为止尝试过的 p>

 ＆lt; select style ='width：112px;'  name ='PayMonth'＆gt; 
＆lt; option name =“PayMonth”value =''＆gt;选择月＆lt; /选项＆gt;  
＆lt;？php 
for（$ i = 1; $ i＆lt; = 12; $ i ++）
 {
 $ allmonth = date（“F”，mktime（0,0,0，$ i，1，  date（“Y”）））
？＆gt; 
＆lt; option value =“＆lt;？php echo $ i;？＆gt;”  ＆gt;＆lt;？php echo date（“F”，mktime（0,0,0，$ i，1，date（“Y”）））;？＆gt; 
＆lt; / option＆gt; 
＆lt;？php \  n}？＆gt; 
  code>  pre> 
 
 这将显示所有月份 p> 
 
 
但是如何显示当月的3个月 
 
 
即， p> 
 
 
 如果当前月份是4月，则应显示2月，3月，4月 strong>  p> 
 \  n 
 如果当前月份是jan，它应该显示nov，dec，jan  strong>  p> 
 
 
我试过..  p> 
 
 

  ＆lt;？php 
 
 $ month = date（“m”）; 
 
？＆gt; 
  code>  pre> 
 
 但在循环中我 与 p> 
 
 
 混淆（$ i = 1; $ i＆lt; = $ month; $ i ++）
  code>  pre> 
  div  >

答

If you are getting $month = date("m"); Then your forloop should be

for($i = $month-3 ; $i <= $month; $i++)

Sidenote :

As you are using

<option value="<?php echo $i; ?>" ><?php echo date("F",mktime(0,0,0,$i,1,date("Y")));?>

You may get -1, -2 inside the values. So you should change

<option value="<?php echo date("m",mktime(0,0,0,$i,1,date("Y"))); ?>" ><?php echo date("F",mktime(0,0,0,$i,1,date("Y")));?>

To get

<select style='width: 112px;' name='PayMonth'>
  <option name="PayMonth" value=''>Select Month</option>   
  <option value="11" >November  </option>
  <option value="12" >December  </option>
  <option value="01" >January  </option>
  <option value="02" >February  </option>   
</select>

答

Just do:

date('m', strtotime('-1 month'));

to get last month.

You can put -2 or -3 to get 2 months ago or 3 months ago also.

Substitute 'm' with the format of your choice.

答

Easy as cake:

echo date('Y-m-d', strtotime("first day of -1 month"));

And you can substitute -1 with the number of your choice:

<?php
foreach(range(-1,-3,-1) as $value) {
    echo date('Y-m-d', strtotime(sprintf("first day of %d month", $value)));
}

答

Try this..

echo date('M', strtotime('0 month'));
echo date('M', strtotime('-1 month'));
echo date('M', strtotime('-2 month'));
echo date('M', strtotime('-3 month'));

答

Take into consideration that you will get wrong results when using months back using the current day - on every 31st day the month.

Try this instead:

<?
$monthsBack = 3;
// we need to do set day to middle of the month,
// otherwise "-x month" will return wrong results on the 31st of each month:
$now =  mktime(0, 0, 0, date("m"), 15, date("Y"));

for ($i1=0; $i1<$monthsBack; $i1++) {
    $displayDate = strtotime("-{$monthsBack} month", $now);
    echo '<option value="'.date("m", $displayDate).'" >'.date("F", $displayDate).'</option>';
}
?>

答

// Today is 2015-02-30
echo date('Y-m-d', strtotime('last month'));

在PHP中获得前几个月

相关推荐