正则表达式从PHP中的字符串中获取所有@提到的用户数据

问题描述：

I have below string. This string having data (@[ID:username__FULLNAME]) of three users mentioned. I want to extract them. I have tried below code but not getting desired results.

ID is integer type
username and FULLNAME may contain numbers, letter and all kind of special chars.


$t = 'Hi @[4232:mark__MΛRK ATTLEY] how are you ? 
    Hi @[4232:ryan__RYΛN вυηту] how are you ? 
    Hi @[4232:david__DΛVID शाहिद ] how are you ? 
    ';

My PHP CODE:

$pattern = "|(?:(@\[[0-9]+:[\s\S(?!\])]+\]*))|";
preg_match_all($pattern, $string, $mentionList, PREG_PATTERN_ORDER);
print_r($mentionList);

Current Result:

Array
(
    [0] => Array
        (
            [0] => @[4232:mark__MÎ›RK ATTLEY] how are you ? 
    Hi @[4232:ryan__RYÎ›N вυηту] how are you ? 
    Hi @[4232:david__DÎ›VID शाहिद] how are you ? 

        )

    [1] => Array
        (
            [0] => @[4232:mark__MÎ›RK ATTLEY] how are you ? 
    Hi @[4232:ryan__RYÎ›N вυηту] how are you ? 
    Hi @[4232:david__DÎ›VID शाहिद] how are you ? 

        )

)

Expected Result:

Array
(
    [0] => Array
        (
            [0] => @[4232:mark__MÎ›RK ATTLEY]
            [1] => @[4232:ryan__RYÎ›N вυηту]
            [2] => @[4232:david__DÎ›VID शाहिद ]
        )

)

Can someone help me getting the desired results?

Thanks.

我有以下字符串。此字符串包含三个用户的数据（@ [ID：username__FULLNAME]）。我想提取它们。我试过下面的代码，但没有得到理想的结果。 p>

  ID是整数类型
username，FULLNAME可能包含数字，字母和所有类型的特殊字符。
 
 
 $ t ='Hi @ [4232：mark__MΛRK  ATTLEY]你好吗？  
嗨@ [4232：ryan__RYΛNвυηту]你好吗？  
嗨@ [4232：david__DΛVIDशाहिद]你好吗？  
'; 
  code>  pre> 
 
 我的PHP代码： p> 
 
 
  $ pattern =“|（？：（@ \  [[0-9] +：[\ s \ S（？！\]）] + \] *））|“; 
 npreg_match_all（$ pattern，$ string，$ prompList，PREG_PATTERN_ORDER）; 
print_r（$ desiredList）  ; 
  code>  pre> 
 
 当前结果： p> 
 
 
  Array 
（
 [0] =＆gt; Array 
  （
 [0] =＆gt; @ [4232：mark__MÎ> RK ATTLEY]你好吗？
嗨@ [4232：ryan__RYγ>Nвυηту]你好吗？
嗨@ [4232：david__Dγ> VIDशाहिद] 你怎么样？
 
）
 
 [1] =＆gt;数组
（
 [0] =＆gt; @ [4232：mark__MÎ> RK ATTLEY]你好吗？
嗨@ [4232  ：ryan__RYÎ>Nвυηту]你好吗？
嗨@ [4232：david__Dγ> VIDशाहिद]你好吗？
 
）
 
）
  code>  pre> 
 
  预期结果： p> 
 
 
 数组
（
 [0] =＆gt;数组
（
 [0] =＆gt; @ [4232：mark__MÎ>  RK ATTLEY] 
 [1] =＆gt; @ [4232：ryan__RYÎ>Nвυηту] 
 [2] =＆gt; @ [4232：david__DÎ> VIDश  ाहिद] 
）
 
）
  code>  pre> 
 
 有人可以帮助我获得理想的结果吗？ p> 
 
 
谢谢。 
  div>

答

You can use the following regex: @\[.+\] (demo) that gets you all you have in [] plus the front @.

Check this working php demo

答

You can use this regex with 3 captured groups:

/@\[(\d+):(\S+)\h+(\S+)\h*\]/

RegEx Demo

RegEx Explanation:

@: Match literal @
\[: Match literal [
(\d+): Match 1+ digits and capture it in group #1 for id
:: Match literal :
(\S+): Match 1+ non-whitespace characters and capture it in group #2 for firstName
\h+: Match 1 or more horizontal whitespaces
(\S+): Match 1+ non-whitespace characters and capture it in group #3 for lastName
\h*: Match 0 or more horizontal whitespaces
\]: Match literal ]

答

Not sure if this will give you the exact output you are looking for, but yor regex is a bit too greedy. You can simplify it like this: (?:@\[[0-9]+.+?])

This should return the captured groups separately.

Not sure if the anonymous capture group is needed so it could be simplified down to (@\[[0-9]+.+?]) or possibly even (@\[.+?]).

正则表达式从PHP中的字符串中获取所有@提到的用户数据

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