SQL获取与请求匹配的所有查询
问题描述:
Hey all I am wondering how I could get ALL queries from a table, it only gets the first one and stops
My code:
$result1 = mysql_query("SELECT `to` FROM transactions WHERE `from` = '$user'");
$row = mysql_fetch_row($result1);
$result2 = mysql_query("SELECT `amount` FROM transactions WHERE `from` = '$user'");
$row2 = mysql_fetch_row($result2);
echo "<li>TO</li>";
echo "<li>AMOUNT</li>";
echo "<li>$row[0]</li>";
echo "<li>$row2[0]</li>";
echo "<li>$row[1]</li>";
echo "<li>$row2[1]</li>";
echo "<li>$row[2]</li>";
echo "<li>$row2[2]</li>";
echo "<li>$row[3]</li>";
echo "<li>$row2[4]</li>";
echo "<li>$row[4]</li>";
echo "<li>$row2[5]</li>";
My Database:
嘿所有我想知道如何从表中获取所有查询,它只获取第一个并停止
我的代码: p>
$ result1 = mysql_query(“SELECT`to` FROM transactions WHERE`from` ='$ user'”) ;
$ row = mysql_fetch_row($ result1);
$ result2 = mysql_query(“SELECT`num` FROM transactions WHERE` from` ='$ user'”);
$ row2 = mysql_fetch_row ($ result2);
echo“&lt; li&gt; TO&lt; / li&gt;”;
echo“&lt; li&gt; AMOUNT&lt; / li&gt;”;
echo“&lt; li&gt; $ row [ 0]&lt; / li&gt;“;
echo”&lt; li&gt; $ row2 [0]&lt; / li&gt;“;
echo”&lt; li&gt; $ row [1]&lt; / li&gt;“; \ n echo“&lt; li&gt; $ row2 [1]&lt; / li&gt;”;
echo“&lt; li&gt; $ row [2]&lt; / li&gt;”;
echo“&lt; li&gt; $ row2 [ 2]&lt; / li&gt;“;
echo”&lt; li&gt; $ row [3]&lt; / li&gt;“;
echo”&lt; li&gt; $ row2 [4]&lt; / li&gt;“;
echo”&lt; li&gt; $ row [4]&lt; / li&gt;“;
echo”&lt; li&gt; $ row2 [5]&lt; / li&gt;“;
code > pre>
我的数据库: p>
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答
$row = mysql_fetch_row($result1); will only fetch one row
You need to use while
$query = mysql_query("SELECT `to`, `amount` FROM transactions WHERE `from` = '$user'");
echo "<li>TO</li>";
echo "<li>AMOUNT</li>";
while ($row = mysql_fetch_assoc($query)) {
echo "<li>{$row['to']}</li>";
echo "<li>{$row['amount']}</li>";
}