在PHP中将时间格式从上午9:00更改为09:00 am
Iam having variable with value 9:30 am - 12:00 pm i.e
$val=$shift (o/p 9:30 am - 12:00pm)
I want to convert it to 09:30 am - 12:00pm, i mean i need to add 0 infront of number if time having one digit
Iam变量值为9:30 am - 12:00 pm,即 p>
我想将其转换为09:30 am - 中午12点,我的意思是如果时间有一位数,我需要在数字前面添加0 p>
div> $ val = $ shift(o / p 9:30 am - 12:00 pm)
code> pre>
Assuming you are saving your time in your database as a string as 9:30 am - 12:00pm
you can just split them. Then format each data.
$val= "9:30 am - 12:00pm";
$splittedString = explode('-', $val);
$time1 = date('h:ia',strtotime($splittedString[0]));
$time2 = date('h:ia',strtotime($splittedString[1]));
echo $time1." - ".$time2;
If you are using date
function then you can format time using h
.
For example
echo date('h:ia'); // output 09:50am
See Referance
If you have values from DataBase as you mentioned in comment then you need to apply PHP's built-in function strtotime()
before formatting the time.
For Example
echo date( 'h:ia', strtotime('9:30 am') ); // output 09:50am
Try
echo date('h:ia',strtotime("9:30 am"))." - ".date('h:ia',strtotime("12:00pm"));