如何根据选择的另一个选择选项更改选择选项?

问题描述：

这是我的html.

<select id="type">
<option value="item1">item1</option>
<option value="item2">item2</option>
<option value="item3">item3</option>
</select>

<select id="size">
<option value="">-- select one -- </option>
</select>

这是我尝试过但未成功的jQuery.

here is the jquery i tried but was unsuccessful.

$(document).ready(function() {

if( $("#type").val("item1"))
{
  $("#size").html("<option value='test'>test</option><option value="test2">test2</option>);
}
elseif( $("#type").val("item2"))
{
   $("#size").html("<option value='anothertest1'>anothertest1</option>");
}

});

基本上，我想做的是，如果在#type中选择了一个选项，则将使用与之关联的选项填充选择的大小.我该怎么办?

basically what i'm trying to do is if an option is selected in #type then the size select is populated with options associated to it. how can i do this?

谢谢

答

以下是您要尝试执行的操作的示例=>

Here is an example of what you are trying to do => fiddle

$(document).ready(function () {
    $("#type").change(function () {
        var val = $(this).val();
        if (val == "item1") {
            $("#size").html("<option value='test'>item1: test 1</option><option value='test2'>item1: test 2</option>");
        } else if (val == "item2") {
            $("#size").html("<option value='test'>item2: test 1</option><option value='test2'>item2: test 2</option>");
        } else if (val == "item3") {
            $("#size").html("<option value='test'>item3: test 1</option><option value='test2'>item3: test 2</option>");
        } else if (val == "item0") {
            $("#size").html("<option value=''>--select one--</option>");
        }
    });
});

<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<select id="type">
    <option value="item0">--Select an Item--</option>
    <option value="item1">item1</option>
    <option value="item2">item2</option>
    <option value="item3">item3</option>
</select>

<select id="size">
    <option value="">-- select one -- </option>
</select>

如何根据选择的另一个选择选项更改选择选项?

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