如何从URL获取当前的Web目录？

问题描述：

If I have a URL that is http://www.example.com/sites/dir/index.html, I would want to extract the word "sites". I know I have to use regular expressions but for some reason my knowledge of them is not working on PHP.

I am trying to use :

 $URL = $_SERVER["REQUEST_URI"];
 preg_match("%^/(.*)/%", $URL, $matches);

But I must be doing something wrong. I would also like it to have a catch function where if it is at the main site, www.example.com then it would do the word "MAIN"

Edit: sorry, I've known about dirname...It gives the full directory path. I only want the first directory.... So if its www.example.com/1/2/3/4/5/index.html then it returns just 1, not /1/2/3/4/5/

如果我的网址 http://www.example.com/sites/dir/index.html ，我想提取”网站“这个词。我知道我必须使用正则表达式，但由于某种原因，我对它们的了解不适用于PHP。 p>

我正在尝试使用： p>

   $ URL = $ _SERVER [“REQUEST_URI”]; 
 preg_match（“％^ /（。*）/％”，$ URL，$ matches）; 
  code>  pre> 
 \  n 但我一定做错了。 我还希望它有一个catch函数，如果它在主站点www.example.com然后它会做“MAIN”这个词 p> 
 
 
编辑：对不起，我' 我知道dirname ...它给出了完整的目录路径。 我只想要第一个目录......所以如果它是www.example.com/1/2/3/4/5/index.html那么它只返回1，而不是/ 1/2/3 / 4/5 /   p> 
  div>

答

Use the dirname function like this:

$dir =  dirname($_SERVER['PHP_SELF']);
$dirs = explode('/', $dir);
echo $dirs[0]; // get first dir

答

The dirname function should get you what you need

http://us3.php.net/manual/en/function.dirname.php

<?php
    $URL = dirname($_SERVER["REQUEST_URI"]);
?>

答

Use parse_url to get the path from $_SERVER['REQUEST_URI'] and then you could get the path segments with explode:

$_SERVER['REQUEST_URI_PATH'] = parse_url($_SERVER['REQUEST_URI'], PHP_URL_PATH);
$segments = explode('/', substr($_SERVER['REQUEST_URI_PATH'], 1));

echo $segments[1];

答

Just wanted to recommend additionally to check for a prefixed "/" or "\" and to use DIRECTORY_SEPARATOR :

$testPath = dirname(__FILE__);
$_testPath = (substr($testPath,0,1)==DIRECTORY_SEPARATOR) ? substr($testPath,1):$testPath;
$firstDirectory = reset( explode(DIRECTORY_SEPARATOR, dirname($_testPath)) );
echo $firstDirectory;

答

A simple and robust way is:

$currentWebDir = substr(__DIR__, strlen($_SERVER['DOCUMENT_ROOT']));

If you are worried about DIRECTORY_SEPARATORS, you could also do:

$currentWebDir = str_replace('\\', '/', substr(__DIR__, strlen($_SERVER['DOCUMENT_ROOT'])));

Also be aware of mod_rewrite issues mentioned by FrancescoMM

如何从URL获取当前的Web目录？

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