正则表达式如何实现，匹配以*开头的一行？

问题描述：

匹配下面代码中以*开头的行

 public class TransferForm extends BaseObject{
    /**
     * This field was generated by MyBatis Generator.
     * This field corresponds to the database column GC_TRANSFER_FORM.FORM_ID
     *
     * @mbggenerated Wed Jan 04 13:58:02 CST 2017
     */
    private String formId;

}

答

/^\s**[^\n]+$/gm，记得加m选项，多行匹配


<textarea id="ta">
    public class TransferForm extends BaseObject{
    /**
    * This field was generated by MyBatis Generator.
    * This field corresponds to the database column GC_TRANSFER_FORM.FORM_ID
    *
    * @mbggenerated Wed Jan 04 13:58:02 CST 2017
    */
    private String formId;

    }
</textarea>
<script>
    var s = ta.value, mc = s.match(/^\s*\*[^\n]+$/gm);
    console.log(mc)
</script>

答

正则表达式为：^\s**

答

[test@localhost shell]$ cat test.txt
public class TransferForm extends BaseObject{
/**

This field was generated by MyBatis Generator.
This field corresponds to the database column GC_TRANSFER_FORM.FORM_ID *
@mbggenerated Wed Jan 04 13:58:02 CST 2017 */ private String formId;

}
[test@localhost shell]$ cat test.txt |sed 's/^[[:space:]]*//g'|grep '^*'

This field was generated by MyBatis Generator.
This field corresponds to the database column GC_TRANSFER_FORM.FORM_ID *
@mbggenerated Wed Jan 04 13:58:02 CST 2017 */_

cat test.txt |sed 's/^[[:space:]]*//g'|grep '^*'
先将行首的空格都去掉，之后筛选出以*开头的行。
不知道你是不是这意思~~~

正则表达式如何实现，匹配以*开头的一行？

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