错误：类mysqli的对象无法转换为字符串

问题描述：

I know that this question has been asked several times on this platform, however, none of them is able to solve my problem.

I am getting this error from the code below.

//This is working
$edition=mysqli_query($con,"select Price from books where Name='$book'");

//This is showing an error. The query is working when I run it on phpmyadmin.
//$edition=mysqli_query($con,"select Price from books where Name='$book' and Edition='$edition'");

//I am using mysqli_fetch_assoc to store it in $row and use the answer for later.
$row = mysqli_fetch_assoc($edition);

Let me know the problem and solution. Thanks in advance. :)

我知道这个问题在这个平台上被多次询问过，但是，他们都没有能够解决我的问题问题。 p>

我从下面的代码中收到此错误。 p>

  //这是有效的
 $ edition = mysqli_query（$ con，“选择图书中的价格= Name ='$ book'”）; 
 
 // 这显示错误。 当我在phpmyadmin上运行它时，查询正在运行。
 // $ edition = mysqli_query（$ con，“从书籍中选择价格，其中Name ='$ book'和Edition ='$ edition'”）; 
 
 /  /我正在使用mysqli_fetch_assoc将其存储在$ row中并稍后使用该答案。
 $ row = mysqli_fetch_assoc（$ edition）; 
  code>  pre> 
 
 让我知道 问题和解决方案。 提前致谢。  ：） p> 
  div>

答

Here we go then :)

Considering in your working example the variable $book already been used, my bet would be on the only other variable $edition. I was thinking if you could debug the code and check the value assigned to it just before using it to make your query, you could confirm if it is a acceptable type.

错误：类mysqli的对象无法转换为字符串

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