在smarty中检索链接的一部分

问题描述：

I have the following link:

http://anydomainname.com/user/username/about

I know that $smarty.server.REQUEST_URI will return user/username/about.

But I can't find a way to return the latest part of my link which is about.

How can I return it? I prefer a solution that does not require me to alter or add new functions in .php files.

我有以下链接： p>

http://anydomainname.com/user/username/about p> blockquote>

我知道$ smarty.server.REQUEST_URI code>将返回 user / username / about code>。 p>
但是我找不到一种方法来返回我的链接的最新部分，即 about code>。 p>
我该如何归还？我更喜欢不需要在.php文件中更改或添加新功能的解决方案。 p> div>

答

Here's an alternative to Marcin's answer using PHP's basename() function instead of substr/strrpos:

{$smarty.server.REQUEST_URI|basename}

答

You can use:

{$smarty.server.REQUEST_URI|substr:($smarty.server.REQUEST_URI|strrpos:'/'+1)}

It finds the last / in this string and return everything after it.

It is working in Smarty 3.1.19

在smarty中检索链接的一部分

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