需要在active-directory中显示用户的信息

问题描述：

The following code will search for the user within the domain controller, but I want to display the info of each thing noted within the justthese variable: "displayname","mail","samaccountname","sn","givenname","department","telephonenumber"

$dn = "dc=xxx,dc=xxx";
$justthese = array("displayname","mail","samaccountname","sn","givenname","department","telephonenumber");

$sr=ldap_search($ldapconn, $dn,'SAMAccountName=username', $justthese);

$info = ldap_get_entries($ldapconn, $sr);

echo "<h3>".$info["count"]." entries returned</h3>";

foreach($justthese as $key=>$value){
    print '<p><strong>'.$value.'</strong></p>';
}

It displays each item within the $justthese array, I want to display the info for that user for each thing noted in $justthese array.

Right now it outputs it like this:

displayname

mail

samaccountname

givenname

department

telephonenumber

I want it to have the actual data to the right of it, which I know I am doing something wrong with the foreach loop, any help is appreciated.

So it'd look like this

displayname Chuck

mail chuck@norris.com

samaccountname chucknorris

sn chuckisthebest

givenname Chuck Norris

department Security

telephonenumber 555-555-5555

以下代码将搜索域控制器中的用户，但我想显示每个注意事项的信息在justthese变量中：“displayname”，“mail”，“samaccountname”，“sn”，“givenname”，“department”，“telephonenumber” p>

  $ dn =“  dc = xxx，dc = xxx“; 
 $ justthese = array（”displayname“，”mail“，”samaccountname“，”sn“，”givenname“，”department“，”telephonenumber“）; 
 
 $  sr = ldap_search（$ ldapconn，$ dn，'SAMAccountName = username'，$ justthese）; 
 
 $ info = ldap_get_entries（$ ldapconn，$ sr）; 
 
echo“＆lt; h3＆gt;”。$ info [  “count”]。“条目返回＆lt; / h3＆gt;”; 
 
foreach（$ justthese as $ key =＆gt; $ value）{
 print'＆lt; p＆gt;＆lt; strong＆gt;'。$ value。'＆lt  ; / strong＆gt;＆lt; / p＆gt;'; 
} 
  code>  pre> 
 
 它显示$ justthese数组中的每个项目，我想显示该用户的信息 对于$ justthese数组中注明的每一件事。 p> 
 
 
现在它输出如下： p> 
 
 
 displayname  p> 
 
 
邮件 p> 
 
 
 samacc  ountname  P> 
 
 
 SN  P> 
 
 
给定名称 P> 
 
 
系 P> 
 
 
 telephonenumber  
 
 
我希望它拥有它右侧的实际数据，我知道我对foreach循环做错了，任何帮助都表示赞赏。 p> 
 
  
所以它看起来像这样 p> 
 
 
 displayname Chuck  p> 
 
 
 mail chuck@norris.com  p> 
 
 
 samaccountname chucknorris  p> 
 
 
 sn chuckisthebest  p> 
 
 
 givenname Chuck Norris  p> 
 
 
部门安全 p> 
 \  n 
电话号码555-555-5555  p> 
  div>

答

Assuming your $info returns just one user: (though you should probably loop through the user array or at least print_r it to see what it's returning)

foreach($justthese as $key=>$value){
    print '<p><strong>'.$value.' ' . (isset($info[0][$value]) ? $info[0][$value] : 'empty') . '</strong></p>';
}

答

Aren't you simply looping trough the wrong array? You probably want to loop trough $info I think?

需要在active-directory中显示用户的信息

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