Php数组按日期下降合并和排序

问题描述：

I need to combine 2 arrays coming from data base (each one ordered by date descent) and echo a new one together by date descent. Studying php sort functions I got to this code:

//Function
function dateSort($a,$b){
$dateA = strtotime($a['data']);
$dateB = $b['payment_date'];//already unixtime
return ($dateA-$dateB);
}

// Merge the arrays
$h_pp_ps = array_merge($h_pp,$h_ps);
// Sort the array using the call back function
usort($h_pp_ps, 'dateSort');
//PRINT!!
print_r($h_pp_ps);

This will produce results from low date to high.... how to get it from high to low?

我需要组合2个来自数据库的数组（每个数据按日期下降排序）并一起回显一个新数组按日期下降。学习php排序函数我得到了这段代码： p>

  // Function 
function dateSort（$ a，$ b）{
 $ dateA = strtotime（$ a ['data  ']）; 
 $ dateB = $ b ['payment_date']; //已经是unixtime 
return（$ dateA- $ dateB）; 
} 
 
 //合并数组
 $ h_pp_ps = array_merge（  $ h_pp，$ h_ps）; 
 //使用回调函数
nortort（$ h_pp_ps，'dateSort'）排序数组; 
 // PRINT !! 
print_r（$ h_pp_ps）; 
  code>   pre> 
 
 这会产生从低日期到高日的结果....如何从高到低？ p> 
  div>

答

Nothing easier:

$h_pp_ps = array_reverse($h_pp_ps);

答

Subtract $dateA from $dateB such as ($dateB - $dateA) in the return statement of method 'dataSort', it will reverse the sorting order.

Details:

Change this method

function dateSort($a,$b){
$dateA = strtotime($a['data']);
$dateB = $b['payment_date'];//already unixtime
return ($dateA-$dateB);

}

To:

function dateSort($a,$b){
 $dateA = strtotime($a['data']);
 $dateB = $b['payment_date'];//already unixtime
 return ($dateB - $dateA);

}

Php数组按日期下降合并和排序

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