如何在Go中通过管道将HTTP响应传递给文件？

问题描述：

How do I convert the below code to use streams/pipes so that I don't need to read the full content into memory? Something like: http.Get("http://example.com/").Pipe("./data.txt")

package main
import ("net/http";"io/ioutil")

func main() {
        resp, err := http.Get("http://example.com/")
        check(err)
        defer resp.Body.Close()
        body, err := ioutil.ReadAll(resp.Body)
        check(err)
        err = ioutil.WriteFile("./data.txt", body, 0666)
        check(err)
}
func check(e error) {
        if e != nil {
                panic(e)
        }
}

如何转换以下代码以使用流/管道，这样我就不需要阅读全部内容类似于： http.Get（“ http://example.com/”）.Pipe（“ ./data.txt”） code> p>

 包main 
import（“ net / http”;“ io / ioutil”）
 
func main（）{
 resp，err：= http.Get（“ http://example.com  /“）
 check（err）
延迟res.Body.Close（）
主体，err：= ioutil.ReadAll（resp.Body）
 check（err）
 err = ioutil.WriteFile（”。  /data.txt“，正文，0666）
 check（err）
} 
func check（e error）{
 if e！= nil {
 panic（e）
} 
} 
   pre> 
  div>

答

How about io.Copy()? Its documentation can be found at: http://golang.org/pkg/io/#Copy

It's pretty simple, though. Give it an io.Reader and an io.Writer and it copies the data over, one small chunk at a time (e.g. not all in memory at once).

So you might try writing something like:

func main() {
  resp, err := http.Get("...")
  check(err)
  defer resp.Body.Close()
  out, err := os.Create("filename.ext")
  if err != nil {
    // panic?
  }
  defer out.Close()
  io.Copy(out, resp.Body)
}

I haven't tested the above; I just hacked it together quickly from your above example, but it should be close if not on the money.

如何在Go中通过管道将HTTP响应传递给文件？

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