如何在SQL查询和PHP中匹配字符串中的单词并检索数据?

如何在SQL查询和PHP中匹配字符串中的单词并检索数据?

问题描述:

I have a MySql Table just like this

Brand 
--------
Honda
Sozuki
Oddi
.
.
.

Now there is an dynamic array in PHP :

$brand = ["Sozuki","Honda"]

The Question is how to retrieve data that matches the word in above array. I tried this :

$qry = 'select * from brand where brand Like '% $brand[0] %' and '% $brand[1] %';

It works fine but what would I do if I have no specific length of array, you can say dynamic array. Any solution will be appreciated Thanks

我有一个像这样的MySql表 p>

  Brand \  n -------- 
Honda 
Sozuki 
Oddi 
。
。
。
  code>  pre> 
 
 

现在PHP中有一个动态数组: p>

  $ brand = [“Sozuki”,“Honda”] 
  code>  pre> 
 
 

问题是如何检索数据 与上面数组中的单词匹配。 我试过这个: p>

  $ qry ='select * from brand brand brand'%$ brand [0]%'和'%$ brand [1]%'; \  n  code>  pre> 
 
 

它工作正常但如果我没有特定长度的数组,我会怎么做,你可以说动态数组。 任何解决方案将不胜感激 p> div>

try

$qry = "select * from brand where brand ";
$i=1;
$count = count($brand); 
foreach($brand as $v) {
  $a = ($i < $count ? 'and' : '');
  $qry .=  " Like '% $v %'  $a ";
  $i++;
}
echo $qry;

You should define array as

$brand = array("Sozuki","Honda");

so then you can use $brand[0], etc ...

$qry = "SELECT * FROM brand WHERE brand LIKE '%{$brand[0]}%' AND '%{$brand[1])%'";

Wouldn't you rather use OR instead of AND?

If so use something like this (note: UNTESTED):

<?php
$brands     = array(1, 2, 3, 7, 8, 9);
$inQuery = implode(',', array_fill(0, count($brands), '?'));

$db = new PDO(...);
$stmt = $db->prepare(
    'SELECT *
     FROM brand
     WHERE brand IN(' . $inQuery . ')'
);

foreach ($brands as $k => $brand)
    $stmt->bindValue(($k+1), $brand);

$stmt->execute();

// Or simply $stmt->execute($brands);

You could try:

$qry = 'select * from brand where brand Like ';
for ($i = 0; $i < sizeof($brands)-1; $i++) {
     $qry .= "'%" . $brand[$i] . "%'";
     if ($i < sizeof($brands) - 2) {
         $qry .= ' AND ';
     }
}

<?php 
$i=0;
$brand=array("Volvo","BMW","Toyota","Honda","Suzuki");
$qry = 'select * from brand where brand Like '% $brand[i] `enter code here`%'';
$i++;
?>