无论如何，不声明结构就将编码的结构作为JSON发送？
问题描述：
I would like to know how I could simplify this piece of code:
type PP struct {
Profile_picture string `json:"profile_picture"`
}
json.NewEncoder(w).Encode(PP {result.Profile_picture})
Something like:
json.NewEncoder(w).Encode({result.Profile_picture})
^ this give me: syntax error: missing operand
And to get rid of:
type PP struct {
Profile_picture string `json:"profile_picture"`
}
Thanks. Sorry for my english.
我想知道如何简化这段代码： p>
type PP struct {
Profile_picture string`json：“ profile_picture”`
}
json.NewEncoder（w）.Encode（PP {result.Profile_picture}）
code> pre >
类似的东西： p>
json.NewEncoder（w）.Encode（{result.Profile_picture}）
code> pre>
^这给了我：语法错误：缺少操作数 code> p>
并摆脱了： p>
type PP struct {
Profile_picture字符串`json：“ profile_picture”`
}
code> pre>
谢谢。 抱歉，我的英文。 p>
div>
答
json.NewEncoder(w).Encode(
map[string]string{"profile_picture": result.Profile_picture},
)
would work — maps with string keys encode to JSON as objects, and you can build up whatever you like with them. It's not shorter, but it does avoid the helper type.
答
Alternatively to hobb's answer, you could also use an anonymous struct.
json.NewEncoder(w).Encode(
struct {
Pp string `json:"profile_picture"`
}{result.Profile_picture},
)