如何获取另一个字符串数组中不存在的字符串数组的值？

问题描述：

I have an array $myArray1 with some string values like 2 5 7 13 23 25. Another array $myArray2 has string values like 2 4 7 11 13 25.

My requirement is to get a third array $myArray3 having only those values of $myArray1 that are not present in $myArray2 i.e. 5 23.

I have tried $myArray3 = array_diff($myArray1, $myArray2) but then $myArray3[0] displays Undefined offset: 0.

Please tell me, is there any function of PHP for this?

我有一个数组$ myArray1 code>，其中包含一些字符串值，如 2 5 7 13 23 25 code>。另一个数组 $ myArray2 code>包含字符串值，如 2 4 7 11 13 25 code>。 p>

我的要求是获取第三个数组 $ myArray3 code>只有 $ myArray1 code>的值， $ myArray2 code>，即 5 23 code>。 p>

我尝试了 $ myArray3 = array_diff（$ myArray1，$ myArray2） code>，但 $ myArray3 [0] code>显示 Undefined offset：0 em>。 p>

请告诉我，PHP有什么功能吗？ p> div>

答

array_diff doesn't reset keys, so you get Undefined offset: 0. If you want them to reset you need to use array_values.

$myArray3 = array_values(array_diff($myArray1, $myArray2));

答

array_diff does not changes the index of the unique values. you can use array_values function to reset the indexes of result array.

try this

 $result = array_values(array_diff($array , $array2));
 print_r($result);