如何将php参数传递给javascript [复制]

问题描述：

Possible Duplicate:
pass php variable value to javascript

I have a piece of php code

function formLetterTabPage($redirect_url, $letter){
  $test = 123;
  foreach (range('A','Z') as $val) {
    if($val == $letter){
        echo '<li class="a" id="li_'.$letter.'" onclick="tab_click('.$letter.')">'.$letter.'</li>';
    }else{
        echo '<li class="b" id="li_'.$val.'" onclick="tab_click('.$letter.')">'.$val.'</li>';
    }
  }
}

and my javascript function tab_click is quite simple:

function tab_click(f){
  alert(f);
}

the key part is here:

echo '<li class="a" onclick="tab_click('.$letter.')">'.$letter.'</li>';

it cannot work out ! so I change it like this:

$test = 123;
echo '<li class="a" onclick="tab_click('.$test .')">'.$letter.'</li>';

it works perfert, and the page show me 123! I wonder why this happen? And I checked the html code, it ok:

<li class="navi_letter_leftb" id="li_A" onclick="tab_click(A)">A</li>

ok, I don't know why?

可能重复： strong>
将php变量值传递给javascript p> blockquote>

我有一段php代码 p>

function formLetterTabPage（$ redirect_url，$ letter）{ $ test = 123; foreach（range）（'A'，'Z'）as $ val）{ if（$ val == $ letter）{ echo'＆lt; li class =“a”id =“li _'。$ letter。'”onclick =“tab_click（'。$ letter。'）”＆gt;'。$ letter。'＆lt; / li＆gt;'; } else { echo'＆lt; li class =“b”id =“li_”。 $ val。'“onclick =”tab_click（'。letter。'）“＆gt;'。$ val。'＆lt; / li＆gt;'; } } } code> pre> 我的javascript函数tab_click非常简单： p> function tab_click（f）{ alert（f）; } code> pre> 关键部分在这里： p> echo'＆lt; li class =“a”onclick =“tab_click（ ” $字母。 '）“＆GT;＆LT' $字母。 '; /锂＆GT;'; 代码> PRE> 它无法解决！所以我改变它是这样的： p> $ test = 123; echo'＆lt; li class =“a”onclick =“tab_click（'。$ test。'）” ＆gt;'。$ letter。'＆lt; / li＆gt;'; code> pre> 它工作正常，页面显示123！我想知道为什么会这样？我检查了html代码，确定： p> ＆lt; li class =“navi_letter_leftb”id =“li_A”onclick =“tab_click（A）”＆gt; A＆lt; / li＆gt; code> pre> 好的，我不知道为什么？ p> div>

答

You need additional quotes in your javascript for string parameters:

echo '<li class="a" onclick="tab_click(\''.$letter.'\')">'.$letter.'</li>';

In your test case $test = 123; you are passing an integer, so the quotes are not needed.

EDIT

Output without quotes (invalid javascript):

<li class="a" onclick="tab_click(a)">a</li>

Output with quotes:

<li class="a" onclick="tab_click('a')">a</li>

答

If you pass $test = 123 your javascript it's working because you're passing an integer value.

But your $letter it's a string and so the resulting html code it's wrong:

<li class="navi_letter_leftb" id="li_A" onclick="tab_click(A)">A</li>

You have to wrap your string between quotes ''. So it should be:

<li class="navi_letter_leftb" id="li_A" onclick="tab_click('A')">A</li>

and you should change your code to:

echo '<li class="a" onclick="tab_click(\''.$letter.'\')">'.$letter.'</li>';

如何将php参数传递给javascript [复制]

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