jQuery单击函数和回调数组
问题描述：
I`m new to jQuery and have a problem understanding functions.
I have the following structure of HTML code:
<ul class="result">
<li id="a"></li>
<li></li> //will be added through a loop depending on input
</ul>
And this jQuery code:
$(document).ready(function() { //changes are possible when the page has fully loaded
$('.inp').keyup(function() { //executes keyup function to the field class "inp"
var inp = $(this).attr('value'); //sets a variable with the value of input from class="inp"
$.post('ajax/file.php', {inp:inp}, function(data) { //posts that value to file.php as variable inp and executes the function (data) to this
$('.result').html(data); //adds the returned result into HTML content as a first element in the set of class="result" => <li>
$('.result li').click(function() { //executes click function when clicking li element
var result_value = $(this).text(); //sets a variable and prepares something as text
$('.inp').attr('value', result_value); //fills value attribute of field class "inp" with the variable result_value
$('.result').html(''); //???
});
});
});
});
Now my question is what $('.result').html(''); does?
答
JQuery .html() property sets the html of the object it is mapped to, it have same behavior like the javascript property .innerHTML.
So here in your scenario $('.result').html(''); will set the html of result class element to null.
<ul class="result">
</ul>
Secondly, you are using wrong approach in your 'file.php', instead use this code:
echo '<li>'.$row["name_1"].'</li>';
echo '<li>'.$row["name_2"].'</li>';
echo '<li>'.$row["name_3"].'</li>';
答
$('.result').html(''); sets the html of .result to a blank string.