如何将数组的所有元素（未知长度）作为单独的参数传递给函数？ [重复]

问题描述：

This question already has an answer here:

How to bind mysqli bind_param arguments dynamically in PHP? 6 answers

I have an array in PHP which may contain data such as this:

$data = array("Apples", "Oranges", "Grapes", "Pears");

I then want to pass these values into the mysqli bind_param function. For this example it would look like this:

$stmt->bind_param("ssss", $data[0], $data[1], $data[2], $data[3]);

My question is how can I produce the same results as above if the length of the array is unknown? For example it may be five, ten or 15 elements long.

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此问题已经存在这里有一个答案： p>

如何在PHP中动态绑定mysqli bind_param参数？ 6 answers span> li> ul> div>

我在PHP中有一个可能包含数据的数组例如： p>

  $ data = array（“Apples”，“Oranges”，“Grapes”，“Pears”）; 
  code>  pre>  
 
 然后我想将这些值传递给 mysqli  code>  bind_param  code>函数。 对于此示例，它将如下所示： p> 
 
 
  $ stmt-＆gt; bind_param（“ssss”，$ data [0]，$ data [1]，$ data [2  ]，$ data [3]）; 
  code>  pre> 
 
 我的问题是，如果数组的长度未知，我怎样才能产生与上面相同的结果？ 例如，它可能是5个，10个或15个元素。 p> 
  div>

答

With PHP 5.6 or higher:

$stmt->bind_param(str_repeat("s", count($data)), ...$data);

With PHP 5.5 or lower you might (and I did) expect the following to work:

call_user_func_array(
    array($stmt, "bind_param"),
    array_merge(array(str_repeat("s", count($data))), $data));

...but mysqli_stmt::bind_param expects its parameters to be references whereas this passes a list of values (thanks Barmar for pointing this out).

You can work around this (although it's an ugly workaround) by first creating an array of references to the original array.

$references_to_data = array();
foreach ($data as &$reference) { $references_to_data[] = &$reference; }
unset($reference);
call_user_func_array(
    array($stmt, "bind_param"),
    array_merge(array(str_repeat("s", count($data))), $references_to_data));

如何将数组的所有元素（未知长度）作为单独的参数传递给函数？ [重复]

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