如何从文本文件中更改一行（PHP）

问题描述：

Text file(text.txt):

#Minecraft server properties
#Tue Sep 23 18:07:26 CEST 2014
generator-settings=
op-permission-level=4
allow-nether=true
level-name=world
enable-query=true
allow-flight=false
announce-player-achievements=true
server-port=25565
query.port=25565
level-type=DEFAULT
enable-rcon=false
force-gamemode=false
level-seed=
server-ip=
max-build-height=256

How to replace the value of some line, such as these:

server-port=25565

Replace with:

server-port=25585

But no to find 'server-port=25565' and replace with 'server-port=25585' It is found that the lines in which the server port and to allocate a value that needs to be replaced.

Example:

<?php
    $myfile = fopen("text.txt", "r") or die("Unable to open file!");
    ...
    fclose($myfile);
?>

EDIT: And when finded this and saved replace the text file.

文本文件（text.txt）： p>

  #Minecraft 服务器属性
＃Tue Sep 23 18:07:26 CEST 2014 
generator-settings = 
op-permission-level = 4 
allow-nether = true 
level-name = world 
enable-query = true 
allow-flight  =假
announce玩家，成就= TRUE 
服务器端口= 25565 
query.port = 25565 
级型= DEFAULT 
enable-RCON =假
Force的游戏模式=假
级种子= 
服务器，IP =  
max-build-height = 256 
  code>  pre> 
 
 如何替换某些行的值，例如： p> 
 
 
  server-port = 25565 
  code>  pre> 
 
 替换为： p> 
 
 
  server-port = 25585 
  代码>  pre> 
 
 但是没有找到'server-port = 25565'并替换为'server-port = 25585'
发现服务器端口所在的行并分配一个 需要替换的值。 p> 
 
 
示例： p> 
 
 
 ＆lt;？php 
 $ myfile = fopen（“text.txt”  ，“r”）或死亡（“无法打开文件！”）; 
 ... 
 fclose（$ myfile）; 
？＆gt; 
  code>  pre> 
 \  n 编辑：
当找到这个并保存时替换文本文件。 p> 
  div>

答

Since your format looks suspiciously like a PHP configuration file (.ini), why not using the parse_ini_file function?

$ini = parse_ini_file("text.txt");
echo "<pre>".print_r($ini,TRUE)."</pre>";

echo $ini["server-port"];

Change it:

$ini["server-port"] = 25585;

Save again your .txt file with:

$f = fopen("text.txt","w");
foreach($ini as $k=>$v) {
   fwrite($f,$k."=".$v.PHP_EOL);
}
fclose($f);

You may need to change your # comments symbol though with ;

UPDATE

$lines = file("text.txt",FILE_IGNORE_NEW_LINES);
// modify
foreach($lines as &$line) {
   $val = explode("=",$line);
   if ($val[0]=="server-port") {
      $val[1] = "25585";
      $line = implode("=",$val);
   }
}
unset($line);

// save again
$f = fopen("text.txt","w");
foreach($lines as $line) {
   fwrite($f,$line.PHP_EOL);
}
fclose($f);

答

You can use strpos() or stripos()

<?php

$file = "file.txt";

$content = file($file);

foreach ($content as $line_num => $line) {
    if (false === (strpos($line, 'server-port=25565'))) continue;

    $content[$line_num] = "server-port=25585
";
}

file_put_contents($file, $content);

Before

#Minecraft server properties
#Tue Sep 23 18:07:26 CEST 2014
generator-settings=
op-permission-level=4
allow-nether=true
level-name=world
enable-query=true
allow-flight=false
announce-player-achievements=true
server-port=25565
query.port=25565
level-type=DEFAULT
enable-rcon=false
force-gamemode=false
level-seed=
server-ip=
max-build-height=256

After

#Minecraft server properties
#Tue Sep 23 18:07:26 CEST 2014
generator-settings=
op-permission-level=4
allow-nether=true
level-name=world
enable-query=true
allow-flight=false
announce-player-achievements=true
server-port=25585
query.port=25565
level-type=DEFAULT
enable-rcon=false
force-gamemode=false
level-seed=
server-ip=
max-build-height=256

Edit

You can modify the $new_port variable to anything you want.

$path = "file.txt";
$new_port = 25585;
$content = file($path);

foreach ($content as $line_num => $line) {
    if (false === (strpos($line, 'server-port'))) continue;

    $content[$line_num] = "server-port=$new_port
";
}

file_put_contents($path, $content);

如何从文本文件中更改一行（PHP）

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