使用ImageMagick更改特定位置的像素颜色值
问题描述:
I have a script like this:
// Loop over image
$size = $im->getImageGeometry();
$w = $size['width'];
$h = $size['height'];
for ($i=0; $i<$w; $i++) {
for ($j=0; $j<$h; $j++) {
$pixel = $im->getImagePixelColor($j,$i);
$color = $pixel->getColor();
$pixel->setColor("rgb(0,0,255)");
}
}
Preferably I'd like the setColor
command to change the color of the pixel at the specified (x,y) location, so that when I call something like:
echo '<img src="data:image/jpg;base64,'.base64_encode($im->getImageBlob()).'" alt="" />';
An updated image will show. However, this does not work since I guess the $pixel
was returned by value instead of by reference. It would actually be preferable if there was a getImagePixelColor
method but I can't seem to find anything on it.
Does anyone know of a way to do this with imagemagick, or maybe recommend a library in php that can do this easily?
答
See this question, "Imagick setColor not working with php". You'll need to initialize a pixel iterator to access a specific pixel, and sync any color changes back to the image.
$image = new Imagick("someimage.png");
$pixel_iterator = $image->getPixelIterator();
foreach($pixel_iterator as $y => $pixels)
{
foreach($pixels as $x => $pixel)
{
$pixel->setColor("rgb(0,0,255)");
}
$pixel_iterator->syncIterator();
}