PHP If语句不重定向空字符串

问题描述：

I have some code that is entering values into a database. I have an IF statement at the start to check if the string $jobno is empty and if it is, it redirects back to the form. But its not redirecting just runs the code successfully.

if ($jobno=='') {
        header( 'Location: add_job.php?error=1');
    }

What am I doing wrong?!

 <?php
$status=$_POST["status"];
$jobno=$_POST["jobno"];
$number=$_POST["number"];
$street=$_POST["street"];
$suburb=$_POST["suburb"];
$city=$_POST["city"];
$first_name=$_POST["first_name"];
$first_name = ucfirst($first_name);
$last_name=$_POST["last_name"];
$last_name = ucfirst($last_name);
$landline=$_POST["landline"];
$mobile=$_POST["mobile"];
$fax=$_POST["fax"];
$email=$_POST["email"];

if ($jobno=='') {
    header( 'Location: add_job.php?error=1');
}

$con=mysqli_connect("server","user","pass","database");
// Check connection
if (mysqli_connect_errno()) {
  echo "Failed to connect to database: " . mysqli_connect_error();
}

mysqli_query($con,"INSERT INTO jobs (status, jobno, number, street, suburb, city, first_name, last_name, landline, mobile, fax, email)
VALUES ('$status', '$jobno', '$number', '$street', '$suburb', '$city', '$first_name', '$last_name', '$landline', '$mobile', '$fax', '$email')");

mysqli_close($con);

header( 'Location: photo_upload.php?new_job_success=y&jobno=' . $jobno ) ;

?>

答

It could be 2 things

$jobno is not ''
since you aren't returning after your redirect, and you are doing a second redirect a bit later, your header would look like:
- Location: add_job.php?error=1
- Location: photo_upload.php?new_job_success=y&jobno=

put an else clause in your code:

<?php
...
if ($jobno=='') {
    header( 'Location: add_job.php?error=1');
}
else {
  $con=mysqli_connect("server","user","pass","database");
  // Check connection
  if (mysqli_connect_errno()) {
    echo "Failed to connect to database: " . mysqli_connect_error();
  }
  else
  {
    mysqli_query($con,"INSERT INTO jobs (status, jobno, number, street, suburb, city,first_name, last_name, landline, mobile, fax, email) VALUES ('$status', '$jobno', '$number', '$street', '$suburb', '$city', '$first_name', '$last_name', '$landline', '$mobile', '$fax', '$email')");

    mysqli_close($con);

    header( 'Location: photo_upload.php?new_job_success=y&jobno=' . $jobno ) ;
  }
}

?>

答

I think you must to use isset function. http://php.net/manual/en/function.isset.php

答

try using this code:

if (!isset($_POST["jobno"])) {
    header( 'Location: add_job.php?error=1');
}

答

 <?php
^---this space

is OUTSIDE of your code, so it's output, which makes

header( 'Location: add_job.php?error=1');

cause a "headers already sent" error.

You are also wide open and begging for an SQL injection attack

答

There is an space in the starting which is causing this error. You can't echo any output before sending the headers not even a single space. This small space is causing the header already sent error.You should remove the space on the starting of the php file. Your code should look like this

<?php
$status=$_POST["status"];

I hope this helps you

PHP If语句不重定向空字符串

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