如何在php和json中访问特定值

问题描述：

I'm using a token:

$url = "https://api.pipedrive.com/v1/deals?api_token=3bd884bb0078f836a56f1464097fb71eac9d50ce";

and here's the json text(not everything);

    {
     "success":true,
     "data":[{
            "id":1,
            "creator_user_id":{
                        "id":1682756,
                        "name":"Kamilah",
                        "email":"kamilah@fractal.ae",
                        "has_pic":false,
                        "pic_hash":null,
                        "active_flag":true, 
                        "value":1682756},
                        "title":"FFS Organization deal"
            }]
    }

I wanted to display "title" and I always get an error

Notice: Undefined index: creator_user_id in C:\xampp\htdocs\pipedrive\getjson.php on line 8

Here's my code so far:

$url = "https://api.pipedrive.com/v1/deals?api_token=3bd884bb0078f836a56f1464097fb71eac9d50ce";

$response = file_get_contents($url);
$object = json_decode($response, true);

echo $object['data']['creator_user_id']['title'];

I'm new to json so I'm just practicing and trying to figure out how to echo a specific value in php. Would be appreciated if you can explain exactly how it works when you echo from json to php.

Thank you! :)

我正在使用令牌： p>

  $ url =  “https://api.pipedrive.com/v1/deals?api_token=3bd884bb0078f836a56f1464097fb71eac9d50ce";

这里是json文本（不是所有内容）; p >

  {
“success”：true，
“data”：[{
“id”：1，
“creator_user_id”：{
“id”：1682756  ，
“名称”：“Kamilah”，
“电子邮件”：“kamilah@fractal.ae”，
“has_pic”：false，
“pic_hash”：null，
“active_flag”：true，\  n“值”：1682756}，
“标题”：“FFS组织交易”
}] 
} 
  code>  pre> 
 
 我想显示“标题” 我总是收到错误 p> 
 
 
 
 注意：未定义的索引：第8行的
 C：\ xampp \ htdocs \ pipedrive \ getjson.php中的creator_user_id  p>  
  blockquote> 
 
 
到目前为止，这是我的代码： p> \  n 
 
  $ url =“https://api.pipedrive.com/v1/deals?api_token=3bd884bb0078f836a56f1464097fb71eac9d50ce";
nnnR响应= file_get_contents（$ url）; 
 $ object =  json_decode（$ response，true）; 
 
echo $ object ['data'] ['creator_user_id'] ['title']; 
  code>  pre> 
 
 我是 json的新手，所以我只是练习并试图弄清楚如何回应php中的特定值。 如果您能从json回复到php时确切地解释它是如何工作的，将不胜感激。 p> 
 
 
谢谢！  ：） p> 
  div>

答

First of all you need to debug the array after using json_decode().

<?php
$url = "https://api.pipedrive.com/v1/deals?api_token=3bd884bb0078f836a56f1464097fb71eac9d50ce";

$response = file_get_contents($url);
$object = json_decode($response, true);
echo "<pre>";
print_r($object); // this will print all data into array format.
?>

As per this array, you do not have title index inside the creator_user_id array. title is a separate index.

Also note that, $object['data'] containing two indexes not one. you can get title as:

<?php
foreach ($object['data'] as $key => $value) {
    //print_r($value); // this will print the values inside the data array.
    echo $value['title']."<br/>"; // this will print all title inside your array.
}
?>

Result:

FFS Organization deal
Google deal

如何在php和json中访问特定值

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