如何显示不同大小的动态加载图像？
问题描述：
How to display dynamically loaded images if more than 1 has different styles or sizes?
My code:
if ($imgcount == 3) {
<div class="style_imgsize">
$dir_path = $photo['file_path'];
$size = getimagesize($dir_path);
echo imagesize($size['0'],$size['1'], $dir_path);
}
function imagesize($width, $height, $src){
switch ($width & $height & $src) {
case "300" > "$width":
echo '<img src="'.$src.'"; width="100" height="100" />';
break;
case "300"<"$height":
echo '<img src="'.$src.'" width="220" height="250" />';
break;
case "$height" > "$width":
echo '<img src="'.$src.'" height="100%" />';
break;
default:
echo "something";
}
}
Example with 3 images with different width, height and styles:
Image 2:
I am getting sizes and width but I need to get every image separate. How to split $imagecount?
答
You can resize it like below:
if (!empty($width) && !empty($height) && !empty($src)) {
if ($width < 300) {
echo '<img src="'.$src.'"; width="100" height="100" />';
} else if ($height < 300) {
echo '<img src="'.$src.'" width="220" height="250" />';
} else if ($height > $width) {
echo '<img src="'.$src.'" height="100%" />';
}
}
Hope this helps.