PHP：通过引用传递数组失败

问题描述：

I've the following code function:

function foo(&$vett) {

    $vettore = $vett;

    $vettore[] = "ciao";

    var_dump($vettore);
}

$v = array();

foo($v);

var_dump($v);

When I dump the final array is empty. Have you any idea of what could be?

我有以下代码函数： p>

  function foo  （＆amp; $ vett）{
 
 $ vettore = $ vett; 
 
 $ vettore [] =“ciao”; 
 
 var_dump（$ vettore）; 
} 
 
 $ v =  array（）; 
 
foo（$ v）; 
 
var_dump（$ v）; 
  code>  pre> 
 
 当我转储时，最终数组为空。 你知道可能是什么吗？ p> 
  div>

答

Because $v never modified. Inside the function you assign the variable into another variable. So nothing ever happen to the old $vett

try something like:

function foo(&$vett) {
    $vett[] = "ciao";
    echo __LINE__;
    var_dump($vett);
}

$v = array();
foo($v);
var_dump($v);

答

Correct version is:

function foo(&$vett) {
    $vett[] = "ciao";
}

$v = array();
foo($v);
var_dump($v);

PHP：通过引用传递数组失败

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