未定义的变量：第115行的C：\ xampp \ htdocs \ shed \ select.php中的列表[重复]
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it is working nice.. but when i open the page.. its allways give me this message Undefined variable: list in C:\xampp\htdocs\shed\select.php on line 115
when i submit the page it allways gives me right data.. but allways shows me that undefined variable $list
<?php
include("db.php");
if(isset($_POST['submit']))
{
$aa= mysql_real_escape_string($_POST['loco_name']);
$bb=mysql_real_escape_string ($_POST['section']);
$result=mysql_query("select * from loco_detail Where loco_name= '$aa' AND section= '$bb' ") or die (mysql_error());
$Count = mysql_num_rows($result); // count the output amount
if ($Count > 0)
{
while($row = mysql_fetch_array($result))
{
$name = $row["loco_name"];
$section = $row["section"];
$schedule = $row["schedule"];
$repair = $row["repair"];
$action = $row["action"];
$date = strftime("%b %d, %Y", strtotime($row["date"]));
$list .="
<table id=\"table\" border=\"1\" cellpadding=\"2\" cellspacing=\"2\">
<tr>
<td id=\"row\"> $name </td>
<td id=\"row\"> $schedule </td>
<td id=\"row\"> $repair </td>
<td id=\"row\"> $action </td>
<td id=\"row\"> $date </td>
</tr>
</table>
";
}
} else {
$list = "You have no products listed in your store yet";
}
}
?>
here the html code
<body>
<center>
<fieldset>
<legend>Select</legend>
<table>
<form method="post">
<tr><td>Loco Number:</td><td><input type="text" name="loco_name"/></td></tr>
<tr><td>Section:</td><td><select name="section">
<option value="Mechanical">Mechanical</option>
<option value="Electrical">Electrical</option>
</select></td></tr>
<tr><td><input type="submit" name="submit" value="Submit"></td></tr>
</form>
</table>
</fieldset>
</center>
<div >
<?php echo $list; ?>
</div>
</body>
please make me out from here.
</div>
There is a period in front of $list which is invoking string concatenation.
The error message is saying you're trying to use a variable that hasn't been "declared" yet. However these are pretty pointless to fix and just causes you to write a lot more redundant code.
You can disable these in your php.ini by changing: error_reporting to E_ALL & ~E_NOTICE or adding error_reporting(E_ALL & ~E_NOTICE); to the top of the page
In a nut shell you're trying to add on to an existing variable called $list that was never declared.
Example of string concatenation:
You can read more here: PHP String Operators
$string = "Hello "; // Declared
$string .= "World";
$string .= "!";
echo $string;
// Outputs "Hello World!"
Basically to fix your issue change your if statement to the following
if ($Count > 0) {
$list = '';
while($row = mysql_fetch_array($result)) {
$name = $row["loco_name"];
$section = $row["section"];
$schedule = $row["schedule"];
$repair = $row["repair"];
$action = $row["action"];
$date = strftime("%b %d, %Y", strtotime($row["date"]));
ob_start();
?>
<table id="table" border="1" cellpadding="2" cellspacing="2">
<tr>
<td class="row"><?=$name?></td>
<td class="row"><?=$schedule?></td>
<td class="row"><?=$repair?></td>
<td class="row"><?=$action?></td>
<td class="row"><?=$date?></td>
</tr>
</table>
<?
$list .= ob_get_clean();
// rest of code here
}
}