for循环返回第5个计数的字符串1-30和来自使用php匹配数字的mysql数据库的13count

I've created a for loop to count 1-30 and want to match mysql number columns 1 - 30 with its attach string data column name and display string inside for loop.

Mysql structure:

|-------------|-------------|--------------|
| id          | Number      | Name         |
|-------------|-------------|--------------|
| 90          |  3          | Test Data    |
|-------------|-------------|--------------|

tried simular attempts such as:

foreach($db->results() as $result) {
  $count = $result->Number;
  $results = $result->Name;
}
for($i=1;$i<=30;$i++) {
  if($count == $i) {
     echo $results;
  }else{
     echo '';
  }
}

Needing help! Thank you!!!

================================================================================================================================================================

Ok here is what I am trying to accomplish... It works with assigning to the correct number when matching (Thanks for the suggestion). Here is what I have:

$name = array();
$number = array();
foreach($forDB->results() as $for){
   $name = $for->firstname;
   $number = $for->number;
    for($i=1;$i<=30;$i++) {
      if($i<=5){
         if($number == $i) {
            echo $i.' = '.$name;
         }
        } //then the rest of remanding numbers to 30
    }
 }

this echos:

2 = name1

4 = name4

But what I would like to do is also echo the numbers of $i between the numbers and values as:

1

2 = name1

3

4 = name4

5

So I try this but it appends to each value:

$name = array();
$number = array();
foreach($forDB->results() as $for){
  $name = $for->firstname;
  $number = $for->number;
  for($i=1;$i<=30;$i++) {
     if($i<=5){
        if($number == $i) {
          echo $i.' = '.$name.'<br><br>';
        } else {
          echo $i.'<br>';
        }
     } else {
        echo $i;
     }
   }
 }

Results:

2

3

4

5

6

7

1

2 = name2

3

4

5

6

7

1

2

3

4 = Jeff

1 2 3 4 5 6 7 1 2 3 4 5 6 7 1 2 3 4 5 6 7 1 2 3 4 5 6 7