Symfony2：如何返回发送表单请求的页面

问题描述：

I have a link: mysite/productnumber_2.html. On this Site I have a formular in a twig template, the action of this form leads to .../createAssessment.

In my controller I do things like save in a DB.

My question is, how can I go back to the url mysite/productnumber_2.html?

My function in teh controller looks like this:

/**
 *
 * @Route(path = "/createassessment", name="create_assessment", methods = "POST")
 * @param Request $request The Request object
 * @return RedirectResponse
 */
public function createAssessmentAction(Request $request) {
$form = $this->createForm(new AssessmentType());
$form->handleRequest($request);

if ($form->isValid()) {

    $assessment = $form->getData();

    $em = $this->getDoctrine()->getManager();

    $em->persist($assessment);
    $em->flush();

    return $this->redirect( ## WHAT DO I HAVE TO PUT HERE?? ## );
}
}

我有一个链接：mysite / productnumber_2.html code>。在这个网站上我有一个twig模板中的公式，这个表单的动作导致 ... / createAssessment code>。 p>

在我的控制器中，我做的事情就像保存在数据库中。 p>


我的问题是，我怎样才能回到网址 mysite / productnumber_2.html  code>？ p> 
 
 我在teh控制器中的功能如下所示： p> 
 
 
  / ** 
 * 
 * @Route（path =“/ createassessment”，name =“create_assessment”，  methods =“POST”）
 * @param请求$ request Request对象
 * @return RedirectResponse 
 * / 
公共函数createAssessmentAction（Request $ request）{
 $ form = $ this-＆gt; createForm（new  AssessmentType（））; 
 $ form-＆gt; handleRequest（$ request）; 
 
if（$ form-＆gt; isValid（））{
 
 $ assessment = $ form-＆gt; getData（）; \  n 
 $ em = $ this-＆gt; getDoctrine（） - ＆gt; getManager（）; 
 
 $ em-＆gt; persist（$ assessment）; 
 $ em-＆gt; flush（）; 
 
  n返回$ this-＆gt;重定向（##我必须把它放在这里？##）; 
} 
} 
  code>  pre> 
  div>

答

You could redirect for request referer:

return $this->redirect($request->headers->get('referer'));

Or even better for defined route:

return $this->redirect($this->generateUrl('your_route'));

where your_route is path to you mysite/productnumber_2.html page.

Symfony2：如何返回发送表单请求的页面

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