仅从一个表中选择用户，除非不在另一个表中

问题描述：

我们有两个表:

-用户-

id  name    borrower
--  ------  --------
1   Peter   1
2   John    1
3   Mark    1
4   David   0

-贷款-

id  from  to  amount
--  ----  --  ------
1   1     2   100

我需要向用户输出彼得没有借出任何钱且借款人= 1(结果中不包括彼得)的用户，像这样:

I need to output users that Peter hasn't lent any money and that are borrowers=1 (excluding Peter from the results), like this:

id  name    borrower
--  ------  --------
3   Mark    1

现在我被这个查询困扰(不起作用):

Right now I am stuck with this query (doesn't work):

SELECT * 
FROM `users` u 
LEFT OUTER JOIN `lendings` l
ON u.`id` = l.`from`
WHERE l.`from` is null
AND u.`id` != 1
AND u.`borrower` = 1

这是实际代码的简化示例，可以使问题对以后的读者有用/可读.

答

像这样吗?

SELECT 
    *
FROM
    users
WHERE
    id NOT IN (SELECT 
            id
        FROM
            lendings)
        AND borrower = 1;

您可能希望使用不同的列名，因为我相信from和to是mysql中的保留字.

You might want to use different column names as I believe from and to are reserved words in mysql.