评估时如何将参数/参数从一个 javascript 片段传递到另一个

问题描述：

我的目标是使用

new Function(x1, x2, x3, functionBody) 调用.

当我需要将参数传递给函数时，我的问题出现了，这是因为 functionBody 可能会显示为具有全局声明和调用的新 Js 脚本.

My problem appears when i need to pass parameters to the function, this is because functionBody may appear as a new Js script with global declarations and calls.

function main() {
var a = x1;
var b = x2;
var c = x3;
....
....
}

main(); // this is the function that starts the flow of the secondary Js snippets

我有一个脚本负责下载和执行另一个 Js 脚本.每个下载的脚本都通过对 main() 的全局调用执行，调用者脚本不知道该调用.

I have a script responsible for downloading and executing another Js script. each downloaded script is executed by a global call to main(), which is unknown to the caller script.

答

你似乎误解了 Function 构造函数有效.

You seem to be misunderstanding how the Function constructor works.

// This does not create a function with x1, x2, x3 parameters
new Function(x1, x2, x3, functionBody)

// This does 
new Function('x1', 'x2', 'x3', functionBody)

参见 https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Function#Specifying_arguments_with_the_Function_constructor

// Create a function that takes two arguments and returns the sum of those arguments
var adder = new Function('a', 'b', 'return a + b');

// Call the function
adder(2, 6);
// > 8

评估时如何将参数/参数从一个 javascript 片段传递到另一个

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