如何将变量从一个 shell 脚本返回到另一个脚本

问题描述：

我有 2 个 shell 脚本，名为 script1.sh(在本地服务器上执行)和 script2.sh(在我将其传递给 ssh 命令的远程服务器上执行).并且我的 script1.sh 正在连接到 unix 服务器并执行 script2.sh，如下所示.

I have 2 shell scripts called script1.sh (executes on local server ) and script2.sh (executes on remote server which i am passing it to ssh command). and my script1.sh is connecting to unix server and and executing script2.sh as below.

declare RESULT=$(sshpass -p 'password' ssh username@1.2.3.4 "bash -s" < ./script2.sh )

和 script2.sh 进行一些计算并返回一些变量来调用脚本，即 script1.sh

and script2.sh does some calculations and returns some variable to calling script i.e script1.sh

#!/bin/sh
declare var1="fgte"
return var1

我想从在服务器上执行的 script2.sh 返回 var1，并且应该向 script1.sh 返回一些值.我怎样才能做到这一点?我需要读取 script1.sh 中 var1 的值.请帮帮我.

I want to return var1 from script2.sh which is executing on server and should return some value to script1.sh. How can i do that? I need to read the value of var1 in script1.sh. Please help me.

答

最简单的方法是使用 stdout，并将结果打印到你的 script2.sh(使用 echocode> 就像你所做的那样)，并将其收集在 script1.sh 中，例如

The simplest way is to use stdout, and print out the result in your script2.sh (using echo as you've done), and collect it in script1.sh e.g.

#!/bin/sh
result=$(script2.sh $var)

当您从子脚本返回多个值时，这会变得更加复杂，并且您必须描述/解析.然而，对于单一价值，这是一种简单实用的方法.

This becomes more complex as/when you return multiple values from a child script, and you have to delineate/parse. For a single value, however, it's a simple and pragmatic approach.

请注意，这与 shell 脚本退出代码不同，后者传统上用于指示您的脚本是否成功返回.

Note this is distinct from the shell script exit code, which is traditionally used to indicate if your script returned successfully or not.

如何将变量从一个 shell 脚本返回到另一个脚本

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