如何将http请求发送到另一个servlet

问题描述：

在我的项目文件夹中，我们在 ContextPath / WEB-INF / Classes / *下有2个java文件.class 名称是 App1.class 和 App2.class

In my project folder,We have 2 java files under ContextPath/WEB-INF/Classes/*.class names are App1.class and App2.class

如果我想运行 App1 .class ，我需要在浏览器中触发URL。

If I want to Run App1.class,Just i need to trigger URL in browser.

  http://localhost:8080/Mapping/App1

以同样的方式，如果你想触发 App2 .class ，使用以下链接

in the same way,if you want to trigger App2.class,use the following link

 http://localhost:8080/Mapping/App2

我想从 App2 $ c> App1 ，表示如果在浏览器中触发 App1 并带有相应的URL，则会触发 App2 。

I want to trigger App2 from App1,means If you trigger App1 with corresponding URL in browser,It will be trigger App2.

我也不想做任何回复。

我该怎么做。

任何人都可以帮助我。

谢谢。

答

我想从App1触发App2，意味着如果触发App1在浏览器中使用相应的URL，它将触发App2。

I want to trigger App2 from App1,means If you trigger App1 with corresponding URL in browser,It will be trigger App2.

考虑 App1 和 App2 在 Mapping web-app中配置为servlet;您可以使用 RequestDispatcher 到 forward（）请求 App2 。这将发生在服务器端，即浏览器将收到响应，好像它来自 App1 。

Considering App1 and App2 are configured as servlets in your Mapping web-app; you can make use of a RequestDispatcher to forward() the request to App2. This would happen server-side i.e. the browser would receive the response as if its coming from App1.

if (isForwardReqd()) {
    RequestDispatcher rd = request.getRequestDispatcher("App2");
    rd.forward(request, response);
}

请注意 App1 在执行 forward（）之前一定不能提交响应，否则你会得到 IllegalStateException 。

Please, note App1 must not have committed a response before doing the forward(), otherwise you'd get an IllegalStateException.

参考：

http://docs.oracle.com/javaee/7/api/javax/servlet/RequestDispatcher.html

定义一个对象，该对象接收来自客户端的请求并将它们发送到任何资源（例如servlet，HTML文件或JSP文件）服务器。

Defines an object that receives requests from the client and sends them to any resource (such as a servlet, HTML file, or JSP file) on the server.

如何将http请求发送到另一个servlet

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