在PHP中将描述的字符串转换为数组路径

问题描述：

I'd appreciate any help I could get with this — I've been scouring stack overflow and couldn't find anything that directly related with what I'm trying to accomplish.

Issue: I'm trying to update a specific name/value pair in a JSON file, and I'm trying to do it by sending specific parameters through an AJAX call to a PHP file. Two of the parameters are the path (delineated with hyphens) to the name, and the value that I'm swapping in.

A small portion of the JSON:

{
  "character" : 
  {             
    "name" : "Foo",
    "species" : "Bar",
  }
}

Using this JSON as an example, I'm trying to update a specific array value, such as:

$char['character']['name']

I'm passing a variable to the PHP file with the path information, such as:

updater.php?char=character-name&val=Newname

Is there a way to convert the string "character-name" (or any string for that matter with a particular delineation) to the path in an Array, like $char['character']['name']?

我很感激我能得到的任何帮助 - 我一直在寻找堆栈溢出而无法找到任何与我想要完成的事情直接相关的事情。 p>

问题： strong>我正在尝试更新JSON文件中的特定名称/值对，我试图通过AJAX调用发送特定参数到PHP文件来做到这一点。其中两个参数是名称的路径（用连字符描绘），以及我正在交换的值。 p>

JSON的一小部分： p>

{ “character”： { “name”：“Foo”， “species”：“Bar”， } } code> pre> 使用此JSON作为示例，我正在尝试更新特定的数组值，例如： p> $ char [' character'] ['name'] code> pre> 我正在使用路径信息将变量传递给PHP文件，例如： p> \ n updater.php？char = character-name＆amp; val = Newname code> pre> 有没有办法转换字符串“character-name” （或具有特定描述的任何字符串）到数组中的路径，如 $ char ['character'] ['name'] code>？ p> div>

答

To not only read the value at the specified path, but also update the json, I would suggest something like

<?php
function json_replace_path($json, $path, $newValue)
{
    $json = json_decode($json);

    $pathArray = explode('-', $path);
    $currentElement = $json;

    foreach ($pathArray as $part)
    {
        $currentElement = &$currentElement->$part;
    }

    $currentElement = $newValue;

    return json_encode($json);
}

$json = '{"character":{"name":"Foo","species":"Bar","other":{"first_name":"Jeff","last_name":"Atwood"}}}';
echo json_replace_path($json, 'character-name', 'new name') . "
";
echo json_replace_path($json, 'character-species', 'new species') . "
";
echo json_replace_path($json, 'character-other-last_name', 'Bridges') . "
";

Does not support JSON including arrays, though.

答

Something like that should work, I guess :

$a = explode("-", $_GET['char']);
$array = ...; //Your json array here

while (is_array($array) && count($a) > 0)
{
    $array = $array[array_shift($a)];
}

答

$array = explode("-", $_GET['char']);

$char=json_decode(....);  //your json string

$char[$array[0]][$array[1]]=$_GET['val'];

答

Why not just use updater.php?character[name]=Newname? Then you can get it with:

echo $_GET['character']['name'];

Makes much more sense. Why concatenate things and then try and separate them into an array when you can just use an array from the start?

在PHP中将描述的字符串转换为数组路径

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