二进制补码形式

在TC ++编译器中， 5 的二进制表示形式是(00000000000000101). 我知道负数存储为2的补数，因此二进制中的 -5 是(111111111111011).最高有效位(符号位)为1，表示它是负数.

In a TC++ compiler, the binary representation of 5 is (00000000000000101). I know that negative numbers are stored as 2's complement, thus -5 in binary is (111111111111011). The most significant bit (sign bit) is 1 which tells that it is a negative number.

那么编译器如何知道它是 -5 ?如果我们将(111111111111011)上面给出的二进制值解释为无符号数字，结果会完全不同吗?

So how does the compiler know that it is -5? If we interpret the binary value given above (111111111111011) as an unsigned number, it will turn out completely different?

还有，为什么1表示 5 -6(1111111111111010)?

Also, why is the 1's compliment of 5 -6 (1111111111111010)?