如果属性值在另一个数组中，php将从数组中删除[重复]

问题描述：

This question already has an answer here:

How to filter a two dimensional array by value 4 answers

I want to remove all elements from arr2 that have a type contained in arr1:

    arr1 = ['A', 'B', 'C']

    arr2 = [
        [
        'name' => 'jane',
        'type' => 'X'
        ],
        [
        'name' => 'jon',
        'type' => 'B'
        ]
    ]

So jon should be removed. Is there some built in function like array_diff?

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此问题已经存在这里有一个答案： p>

如何按值过滤二维数组 4 answers span> li> ul> div>

我想删除arr2中包含类型的所有元素在arr1： p>

  arr1 = ['A'，'B'，'C'] 
 
 
 arr2 = [
 [
'name'=＆gt;  'jane'，
'type'=＆gt;  'X'
]，
 [
'name'=＆gt;  'jon'，
'type'=＆gt;  'B'
] 
] 
  code>  pre> 
 
 因此应删除jon。 是否有一些内置函数，如array_diff？ p> 
  div>

答

One of solutions using array_filter:

print_r(array_filter(
    $arr2, 
    function($v) use($arr1) { return !in_array($v['type'], $arr1); }
));

答

I don't think there's a way to do it with just one built-in array function, but you can combine some of them to do it.

$record_types = array_column($arr2, 'type');

$records_to_keep = array_diff($record_types, $arr1);

$result = array_intersect_key($arr2, $records_to_keep);

答

Foreach the 2nd array and check if the type is in arr1. If so then simply delete(unset) it.

foreach(array_keys(arr2) as $Key) {
   if (in_array(arr2[$Key]['type'],arr1)) { unset(arr2[$Key]); }
}

答

Here's another if the type is unique:

$result = array_diff_key(array_column($arr2, null, 'type'), array_flip($arr1));

extract an array from $arr2 keyed (indexed) by the type column
flip $arr1 to get values as keys
get the key differences

Run array_values on it to re-index if needed.

如果属性值在另一个数组中，php将从数组中删除[重复]

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