PHP strpos匹配多个干草堆中的所有针

问题描述：

I want to check if ALL words from $words exist in one or more $sentences, word order is not important.

Words will only contain [a-z0-9].

Sentences will only contain [a-z0-9-].

My code so far, it almost work as expected:

$words = array("3d", "4");
$sentences = array("x-3d-abstract--part--282345", "3d-speed--boat-430419", "beautiful-flower-462451", "3d-d--384967");

foreach ($words as $word) {
    $sentences_found = array_values(array_filter($sentences, function($find_words) use ($word) {return strpos($find_words, $word);}));
}
print_r($sentences_found);

If you run this code here http://3v4l.org/tD5t5 , you'll get 4 results, but in reality it should be 3 results

Array
(
    [0] => x-3d-abstract--part--282345
    [1] => 3d-speed--boat-430419
    [2] => beautiful-flower-462451   // this one is wrong, no "3d" in here, only "4"
    [3] => 3d-d--384967
)

How can I do this?

Also is there any better way to do this than strpos?

Regex?

Regex is maybe slow for this job because sometimes there will be 1000's of $sentences (don't ask why).

我想检查$ words中的所有单词是否存在于一个或多个$句子中，单词顺序并不重要。 p>

单词只包含[a-z0-9]。 p>

句子只包含[a-z0-9 - ]。 p >

到目前为止，我的代码几乎按预期工作： p>

  $ words = array（“3d”，“4”）; 
 $  sentence = array（“x-3d-abstract  -  part  -  282345”，“3d-speed-boat-430419”，“beautiful-flower-462451”，“3d-d-384967”）; 
 \  nforeach（$ words as $ word）{
 $ sentences_found = array_values（array_filter（$ sentences，function（$ find_words）use（$ word）{return strpos（$ find_words，$ word）;}））; 
} \  nprint_r（$ sentences_found）; 
  code>  pre> 
 
 如果您在此处运行此代码，请  http://3v4l.org/tD5t5 ，你会得到4个结果，但实际上它应该是3个结果 p> 
 
 
  Array 
（
 [  0] =＆gt; x-3d-abstract  -  part  -  282345 
 [1] =＆gt; 3d-speed  -  boat-430419 
 [2] =＆gt; beautiful-flower-462451 //这个 一个是错的，这里没有“3d”，只有“4”
 [3] =＆gt;  3d-d  -  384967 
）
  code>  pre> 
 
 我该怎么做？ p> 
 
 
还有更好的方法 这是否比strpos？ p> 
 
 
正则表达式？ p> 
 
 
正则表达式对这项工作来说可能很慢，因为有时会有1000个$的句子（不要问 为什么）。 p> 
  div>

答

You could use an intersection of found sentences per word:

$found = array();

foreach ($words as $word) {
    $found[$word] = array_filter($sentences, function($sentence) use ($word) {
        return strpos($sentence, $word) !== false;
    });
}

print_r(call_user_func_array('array_intersect', $found));

Or, approach from $sentences:

$found = array_filter($sentences, function($sentence) use ($words) {
    foreach ($words as $word) {
        if (strpos($sentence, $word) === false) {
            return false;
        }
    }
    // all words found in sentence 
    return true;
});

print_r($found);

One important thing to mention is that your search criteria was wrong; instead of strpos($sentence, $word) you should explicitly compare against false, otherwise you will miss a match at the start of a sentence.

PHP strpos匹配多个干草堆中的所有针

相关推荐